CODEWITHSUNDEEP
ruby-on-railsruby
Leo
Leo

Reputation: 2103

how to convert integer(months) into human friendly string?

I need to translate a number of months, integer based, into a human friendly string containing information about years. its not easy to explain so I will just provide examples. inputs and outputs I want are:

input: 19
output: "1 year, 7 months"

input: 24
output: "2 years"

input: 26
output: "2 years, 2 months"

do you know any out of the box solutions? if not, how would you implement it yourself?

Upvotes: 1

Views: 178

Answers (4)

Les Nightingill
Les Nightingill

Reputation: 6156

Since this question is tagged with Ruby on Rails, ActiveSupport extensions are available, so this works too:

number_of_months = 19 # for example

ActiveSupport::Duration.build(number_of_months.months).inspect.gsub(' and',', ')

Edit I just noticed that there was a bug in ActiveSupport::Duration version 6.0.2.2 that was fixed sometime prior to version 6.1.0.alpha that caused rounding errors for certain values of number_of_months.

Upvotes: 2

Rajagopalan
Rajagopalan

Reputation: 6064

input = 26
year, month = input.divmod(12)
if month.eql? 0 and year > 1
  puts "#{year} years"
elsif month.eql? 0 and year.eql? 1
  puts "#{year} year"
elsif year > 1
  puts "#{year} years, #{month} month"
else
  puts "#{year} year, #{month} month"
end

Output

2 years, 2 month

Upvotes: 2

iGian
iGian

Reputation: 11193

Just for fun:

num.divmod(12).then { |y, m| [y, m].zip ['years', 'months'] }
              .reject{ |e| e.first.zero? }
              .each{ |e| e.last.delete_suffix!('s') if e.first == 1 }
              .join(' ')
              .tap{ |res| res.replace('0 months') if res.empty? }

Samples:

[11, 12, 13, 23, 24, 25, 26].each { |n| p [n, n.divmod(12).then.......] } # pseudo

[11, "11 months"]
[12, "1 year"]
[13, "1 year 1 month"]
[23, "1 year 11 months"]
[24, "2 years"]
[25, "2 years 1 month"]
[26, "2 years 2 months"]

Upvotes: 1

Chiara Ani
Chiara Ani

Reputation: 1083

def pluralize(num, string)
  [num, (num == 1 ? string : "#{string}s")] * ' ' 
end

def humanize_months(months)
  months = input % 12
  years = input / 12
  text = [] 
  text << pluralize(years, 'year') if years > 0
  text << pluralize(months, 'month') if months > 0
  text * ', '
end

Upvotes: 0

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