Reputation: 5499
Can anyone help me get the correct jq command to flatten the below example? I've seen a few other posts and I'm hacking away at it but can't seem to get it. I'd greatly appreciate any help.
Input:
[
{
"name": "level1",
"children": [
{
"name": "level2",
"children": [
{
"name": "level3-1",
"children": []
},
{
"name": "level3-2",
"children": []
}
]
}
]
}
]
Output:
[
{
"displayName": "level1",
"parent": ""
},
{
"displayName": "level2",
"parent": "level1"
},
{
"displayName": "level3-1",
"parent": "level2"
},
{
"displayName": "level3-2",
"parent": "level2"
}
]
Upvotes: 1
Views: 537
Reputation: 116670
Here's a straightforward solution that does not involve a helper function and actually solves a more general problem. It is based on the idea of beginning by adding a "parent" key to each child, and then using ..
to collect all the name/parent pairs.
So first consider:
[ walk(if type=="object" and has("children")
then .name as $n | .children |= map(.parent = $n)
else . end)
| ..
| select(type=="object" and has("name"))
| {displayName: .name, parent}
]
This meets the requirements except that for the top-level (parentless) object, it produces a .parent value of null
. That would generally be more JSON-esque than "", but if the empty string is really required, one has simply to replace the last non-trivial line above by:
| {displayName: .name, parent: (.parent // "")}
Upvotes: 2
Reputation: 50750
With a simple recursive function:
def f: .name as $parent | .children[] | {$parent, displayName: .name}, f;
[ {name: "", children: .} | f ]
Upvotes: 1