CODEWITHSUNDEEP
javascriptregex
422
422

Reputation: 5770

Regex for validating postcode and phone number

I am creating a form, with warning elements. All works great but need to define my patterns better.

                $("#postcode").inputNotes( 
              {
                warning: {
                  pattern: /^[0-9]+$/,
                  type: 'note',
                  text: 'Only numbers, please ...',
                  inversedBehavior: true
                }
              }
            );
            $("#phone").inputNotes( 
              {
                warning: {
                  pattern: /^[0-9]+$/,
                  type: 'note',
                  text: 'Only numbers, no spaces please ...',
                  inversedBehavior: true
                }
              }
            );

Ok for the Postcode warning, I want the pattern to expect 4 numbers

For the Phone warning, I want the pattern to expect 10 numbers.

Any help appreciated.

Upvotes: 4

Views: 16002

Answers (7)

taggartJ
taggartJ

Reputation: 287

just to save people time here is an example of how to use in jquery

 $("#address-postal-code").once().on('blur', function (e) {
    var myRegEx = new RegExp('^(0[289][0-9]{2})|([1-9][0-9]{3})$');
    var ele = $(this);
    if (!myRegEx.test(ele.val())) {
        console.log('no good');
    }
    else {
        console.log('good');
    }
})

Upvotes: 0

Lewis JSMakesMeHard
Lewis JSMakesMeHard

Reputation: 11

All these answers are assuming that you limit the text field to 4 characters eg. (12345) is valid, to limit the length use the following

^(0[289][0-9]{2})$|^([1-9][0-9]{3})$

Upvotes: 1

Timo
Timo

Reputation: 271

Australia Post has greatly simplified the rules in 2019. You now only need to account for the ranges:
0200 – 0299, 0800-0999 and 1000 – 9999

So the Regular Expression for Validating Australian Postcodes is just:

^(0[289][0-9]{2})|([1-9][0-9]{3})$

Upvotes: 11

stuartdotnet
stuartdotnet

Reputation: 3034

Here are the rules for Australian postcodes:

ACT: 0200-0299 and 2600-2639.

NSW: 1000-1999, 2000-2599 and 2640-2914.

NT: 0900-0999 and 0800-0899.

QLD: 9000-9999 and 4000-4999.

SA: 5000-5999.

TAS: 7800-7999 and 7000-7499.

VIC: 8000-8999 and 3000-3999.

WA: 6800-6999 and 6000-6799

Regular Expression: ^(0[289][0-9]{2})|([1345689][0-9]{3})|(2[0-8][0-9]{2})|(290[0-9])|(291[0-4])|(7[0-4][0-9]{2})|(7[8-9][0-9]{2})$

Pass: 0200|||7312|||2415

Fail: 0300|||7612|||2915

Upvotes: 11

Chandu
Chandu

Reputation: 82933

Update:

For 6 digit or 10 digit numbers: pattern: /^[0-9]{10}|[0-9]{6}$/,

For four digit Postcode: pattern: /^[0-9]{4}$/,

For 10 digit Phone number: (if phone number can't start with 0) pattern: /^[1-9][0-9]{9}$/,

(if phone number can start with 0) pattern: /^[0-9]{10}$/,

Upvotes: 6

alex
alex

Reputation: 490433

For a 4 digit postcode, you can use /^\d{4}$/.

For a 10 digit postcode, you can use /^\d{10}$/.

Keep in mind some people will type spaces, parenthesis etc into the phone number. You should strip all non digits first before validating with /[^\d]+/g.

Upvotes: 3

icktoofay
icktoofay

Reputation: 129079

Instead of using the + modifier, try using {num}, where num is the number of instances of the previous atom you want.

Upvotes: 2

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