Reputation: 127
This is similar to my previous question. I have the following partial docket numbers:
docket_number
-------------
2012JV592
2016DR138
2018JV84
If the docket number is less than 10 digits, then I need to insert 0's after the second letter until the lenth is 10 digits. Updated docket numbers would look like this.
docket_number
-------------
2012JV0592
2016DR0138
2018JV0084
Upvotes: 1
Views: 106
Reputation: 14886
Is it the case that your docket_number should always follow the format 4 digits (year?) followed by 2 letters followed by 4 digits. Then simple sub-string of the docket_number and subsequent re-concatenation is sufficient.
select docket_number
, substr(docket_number,1,6) || lpad(nvl(substr(docket_number,7),'0'),4,'0')
from test_dn
where length(docket_number) < 10
order by docket_number;
and for update:
update test_dn
set docket_number = substr(docket_number,1,6) || lpad(nvl(substr(docket_number,7),'0'),4,'0')
where length(docket_number) < 10;
If the format holds true then, depending on table size, this could be significantly faster as regular expressions are relative slow.
Upvotes: 0
Reputation: 65278
You can split the data into three parts as digit group1, letters group, and digit group2 by using regexp_substr()
functions, and lpad()
function in order to add zeroes just before the second digit group, and then concatenate them directly by using ||
operators, assuming that you have the same data model for the whole table,
UPDATE t
SET docket_number = regexp_substr(docket_number,'[[:digit:]]+')||
regexp_substr(docket_number,'[[:alpha:]]+')||
lpad('0',10-length(docket_number),'0')||
regexp_substr(docket_number,'[[:digit:]]+$')
Upvotes: 1
Reputation: 142743
One option might be to
SQL> with test (docket_number) as
2 (select '2012JV592' from dual union all
3 select '2016DR138' from dual union all
4 select '2018JV84' from dual
5 ),
6 temp as
7 (select docket_number,
8 regexp_substr(docket_number, '[[:digit:]]+[[:alpha:]]+') part1,
9 regexp_substr(docket_number, '[[:digit:]]+$') part2
10 from test
11 )
12 select case when length(docket_number) < 10 then
13 part1 || lpad(part2, 10 - length(part1), '0')
14 else docket_number
15 end result
16 from temp;
RESULT
--------------------------------------------------------------------------------
2012JV0592
2016DR0138
2018JV0084
SQL>
How to update rows in a table? By using such a SELECT
in UPDATE
, e.g.
SQL> select * from test;
DOCKET_NUM
----------
2012JV592
2016DR138
2018JV84
SQL> update test a set
2 a.docket_number =
3 (with temp as
4 (select b.docket_number,
5 regexp_substr(b.docket_number, '[[:digit:]]+[[:alpha:]]+') part1,
6 regexp_substr(b.docket_number, '[[:digit:]]+$') part2
7 from test b
8 )
9 select case when length(t.docket_number) < 10 then
10 t.part1 || lpad(t.part2, 10 - length(t.part1), '0')
11 else docket_number
12 end
13 from temp t
14 where t.docket_number = a.docket_number
15 );
3 rows updated.
SQL> select * from test;
DOCKET_NUM
----------
2012JV0592
2016DR0138
2018JV0084
SQL>
Upvotes: 1