CODEWITHSUNDEEP
rubynokogiri
Lupino
Lupino

Reputation: 154

Nokogiri: non-destructively print node without its children

I have a piece of ruby code to replace the value of an attribute:

# -*- coding: utf-8 -*-
require "nokogiri"
    
xml = <<-eos
<a blubb="blah">
  <b>irrelevant</b>
  <b>also irrelevant</b>
  <b blubb="blah">
    <c>irrelevant</c>
    <c>irrelevant</c>
  </b>
  <b blubb="foo">
    <c>irrelevant</c>
    <c>irrelevant</c>
  </b>
</a>
eos

doc = Nokogiri::XML(xml) { |config| config.noent }
doc.xpath("//*[@blubb='blah']").each {|node|
  puts "Node before:\n#{node.to_s}" ## replace me!
  node['blubb'] = "NEW"
  puts "Node after:\n#{node.to_s}" ## replace me!
}

When i execute this code, i get the whole node element printed, but I only need to see the start tag to confirm that my script works correctly. Is there a way to display only the start tags of node, or at least only the element itself without its child nodes? The important thing is that the node itself doesn't change when printed (beside the replacement in the attribute), so removing the children is not an option!

Upvotes: 0

Views: 97

Answers (1)

Navarasu
Navarasu

Reputation: 8479

We can print name and attribute_nodes of the node

doc.xpath("//*[@blubb='blah']").each {|node|
  puts "Node before:\n #{node.name} "+node.attribute_nodes.reduce('') { |out, n| out+="#{n.name}=#{n.value}'"}
  node['blubb'] = "NEW"
  puts "Node after:\n #{node.name} "+node.attribute_nodes.reduce('') { |out, n| out+="#{n.name}='#{n.value}'"}
}

Upvotes: 1

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