Reputation: 3
I am trying to create a loop that allows the user to enter as many elements to the array as they would like then sum up those elements. I need the loop to terminate when the user enters a negative number. How would I go about terminating this?
double sum = 0;
double group[] = { 0 };
for (int i = 0; i >= 0; i++) {
cout << "Please enter employee salary. Enter negative number to end." << endl;
cout << "Employee " << i + 1 << ": $";
cin >> group[i];
if (i < 0) {
break;
}
sum += group[i];
}
cout << "The total salary ouput for Ernest Inc is: $" << fixed << showpoint << setprecision(2) << sum << endl;
Upvotes: 0
Views: 65
Reputation: 17678
I need the loop to terminate when the user enters a negative number.
For that a while
loop would be better than for
. You should also use vector
which allows arbitrary number of items.
Something like this:
vector<double> group;
double salary;
while (true)
{
cout << "Please enter employee salary. Enter negative number to end." << endl;
cout << "Employee " << i + 1 << ": $";
cin >> salary;
if (salary<0)
{
break;
}
group.push_back(salary);
sum += salary;
}
Upvotes: 1