Reputation: 53
I have been trying to follow the example from this tutorial, but I am having trouble training any of the variables.
I wrote a small example, but I haven't been able to make that work either:
# Train a shift bijector
shift = tf.Variable(initial_value=tf.convert_to_tensor([1.0], dtype=tf.float32), trainable=True, name='shift_var')
bijector = tfp.bijectors.Shift(shift=shift)
# Input
x = tf.convert_to_tensor(np.array([0]), dtype=tf.float32)
target = tf.convert_to_tensor(np.array([2]), dtype=tf.float32)
optimizer = tf.optimizers.Adam(learning_rate=0.5)
nsteps = 1
print(bijector(x).numpy(), bijector.shift)
for _ in range(nsteps):
with tf.GradientTape() as tape:
out = bijector(x)
loss = tf.math.square(tf.math.abs(out - target))
#print(out, loss)
gradients = tape.gradient(loss, bijector.trainable_variables)
optimizer.apply_gradients(zip(gradients, bijector.trainable_variables))
print(bijector(x).numpy(), bijector.shift)
For nsteps = 1, the two print statements result in the following output:
[1.] <tf.Variable 'shift_var:0' shape=(1,) dtype=float32, numpy=array([1.], dtype=float32)>
[1.] <tf.Variable 'shift_var:0' shape=(1,) dtype=float32, numpy=array([1.4999993], dtype=float32)>
It seems like the bijector
still uses the original shift
even though the printed value of bijector.shift
has been updated.
I cannot increase nsteps
as the gradient is None
after the first iteration, and I got this error:
ValueError: No gradients provided for any variable: ['shift_var:0'].
I'm using
tensorflow version 2.3.0
tensorflow-probability version 0.11.0
I also tried it on a colab notebook, so I doubt it's a version problem.
Upvotes: 1
Views: 417
Reputation: 1076
You found a bug. The bijector forward function weakly caches the result->input mapping to make downstream inverses and log-determinants fast. But somehow this is also interfering with the gradient. A workaround is adding a del out
, as in https://colab.research.google.com/gist/brianwa84/04249c2e9eb089c2d748d05ee2c32762/bijector-cache-bug.ipynb
Upvotes: 1
Reputation: 53
Still not sure I understand exactly what is going on here, but at least I can get my example to work now.
For some reason the behaviour is different if I wrap it in a class that inherits from tf.keras.Model:
class BijectorModel(tf.keras.Model):
def __init__(self):
super().__init__()
self.shift = tf.Variable(initial_value=tf.convert_to_tensor([1.5], dtype=tf.float32), trainable=True, name='shift_var')
self.bijector = tfp.bijectors.Shift(shift=self.shift)
def call(self, input):
return self.bijector(input)
I made a function for a training iteration, although this does not seem to be necessary:
def training_iteration(model, input, target):
optimizer = tf.optimizers.SGD(learning_rate=0.1)
with tf.GradientTape() as tape:
loss = tf.math.square(tf.math.abs(model(input) - target))
gradients = tape.gradient(loss, model.trainable_variables)
optimizer.apply_gradients(zip(gradients, model.trainable_variables))
Executing like this
x = tf.convert_to_tensor(np.array([0]), dtype=tf.float32)
target = tf.convert_to_tensor(np.array([2]), dtype=tf.float32)
model = BijectorModel()
nsteps = 10
for _ in range(nsteps):
training_iteration(model, x, target)
print('Iteration {}: Output {}'.format(_, model(x)))
produces the expect/desired output:
Iteration 0: Output [1.6]
Iteration 1: Output [1.6800001]
Iteration 2: Output [1.7440001]
Iteration 3: Output [1.7952001]
Iteration 4: Output [1.8361601]
Iteration 5: Output [1.8689281]
Iteration 6: Output [1.8951424]
Iteration 7: Output [1.916114]
Iteration 8: Output [1.9328911]
Iteration 9: Output [1.9463129]
My conclusion is that trainable variables are handled differently when part of a model, compared to being accessed through a bijector-object.
Upvotes: 1