Reputation: 93
const Video = require("");
const token = "";
const connectOptions = {logLevel: "off"}
const startRoom = function(token) {
console.log("hello world");
Video.connect(a)
.then(room => null
})
.catch(error => {
console.log("error");
return error
});
}
The async/await will lead to removal of catch. Which is what I want to achieve.
Upvotes: 1
Views: 171
Reputation: 1
or you can use this also..
async function startRoom(token) {
console.log("hello world");
try {
let response = await fetch(token);
if (!response.ok) {
throw new Error(`HTTP error! status: ${response.status}`);
} else {
let room = await video.connect(token, connectOptions);
console.log("got a room");
}
} catch (e) {
console.log(e);
}
}
Upvotes: 0
Reputation: 162
Just wrap it in try-catch
const getRoom = async () => {
try {
const room = await Video.connect(token, connectOptions);
console.log("got a room");
} catch (e) {
console.log("error");
}
}
Upvotes: 0
Reputation: 13892
Just fyi, you're not using await INSTEAD of promises, you're using await WITH promises. async functions return promises, and await
waits for promises to resolve
const Video = require("twilio-video");
const token = "test_token";
const connectOptions = {video: false, audio: false, logLevel: "off"}
const startRoom = async function(token) {
console.log("hello world");
try {
const room = await Video.connect(token, connectOptions)
console.log("got a room");
} catch(error) {
console.log("error");
}
}
Upvotes: 1