CODEWITHSUNDEEP
phpforms
Aaditya Dulal
Aaditya Dulal

Reputation: 1

A simple number guessing program in php using HTML Form

<html>
  <head>
    <title>Guessing Game</title>
  </head>
  <body>
    <h1>Welcome to my guessing game</h1>
    <form action="" method="GET">
      <label for="numinput">Enter your number</label>
      <input type="text" name="numinput">
      <input type="submit" name="submit">
    </form>

<?php
$num = $_GET['numinput'];
if (!isset($_GET['num'])) {
  echo("Missing Guess Parameter");
} elseif ( strlen($_GET['num']) <60){
  echo ("Your guess is too short");
} elseif ( !is_numeric($_GET['num'])){
  echo("Your guess is not a number");
} elseif ($_GET['num'] > 60){
  echo ("Your guess is too high");
} else {
  echo ("Congratulations - You are right");
}
?>
</html>

My goal is to create a simple number guessing game using $_GET in php Output: "Missing Guess Parameter" despite i provide any number in the input. Also, I couldn't understand whether to get the user provided data from submit of the textbox.

Upvotes: 0

Views: 641

Answers (2)

GNassro
GNassro

Reputation: 1071

Name of the html input and the key of $_GET must be identical, so change name="numinput" to name="num" will be a solution to fixed the problem.

NB: $num = $_GET['num']; may accure UNDEFINED INDEX if you use it outside the if condition when isset($_GET['num']) equal to true

<html>
  <head>
    <title>Guessing Game</title>
  </head>
  <body>
    <h1>Welcome to my guessing game</h1>
    <form action="" method="GET">
      <label for="numinput">Enter your number</label>
      <input type="text" name="num">
      <input type="submit" name="submit">
    </form>

<?php
//$num = $_GET['num']; this should be after isset($_GET['num']) == true
if (!isset($_GET['num'])) {
  echo("Missing Guess Parameter");
} elseif ( strlen($_GET['num']) <60){
  echo ("Your guess is too short");
} elseif ( !is_numeric($_GET['num'])){
  echo("Your guess is not a number");
} elseif ($_GET['num'] > 60){
  echo ("Your guess is too high");
} else {
  echo ("Congratulations - You are right");
}
?>
</body>
</html>

Upvotes: 1

Chilarai
Chilarai

Reputation: 1888

You need to put $num instead of $_GET['num'] after the variable $num is set

<html>
<head>
<title>Guessing Game</title>
</head>
<body>
<h1>Welcome to my guessing game</h1>
<form action="" method="GET">
<label for="numinput">Enter your number</label>
<input type="text" name="numinput">
<input type="submit" name="submit">
</form>

<?php

$num = $_GET['numinput'];


if (!isset($num)) {
    echo("Missing Guess Parameter");}
elseif ( strlen($num) <60){
        echo ("Your guess is too short");}
elseif( !is_numeric($num)){
        echo("Your guess is not a number");}    
elseif ($num > 60){
        echo ("Your guess is too high");}
else{
        echo ("Congratulations - You are right");}
      
?>
</html>

Upvotes: 1

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