CODEWITHSUNDEEP
python
user8141758
user8141758

Reputation: 37

Python next () function

I'm writing program to find unique digits in a number and got this solution but I want to know how this works?

print(next(len(set(list(x))) if 1<=int(x)<=25000 else "Number should be >=1 and <=25000" for x in [input()]))

Upvotes: 2

Views: 90

Answers (2)

Ale
Ale

Reputation: 1004

If you want to "find unique digits in a number" meaning that you want to see which digits are unique then you can use this code:

x = input()
print((list(set(x))) if 1<=int(x)<=25000 else "Number should be >=1 and <=25000")

Upvotes: 1

Riccardo Bucco
Riccardo Bucco

Reputation: 15364

Let's rewrite the solution in another way and comment it:

# Read the number (as a string, for example '3455')
x = input()
# Convert the string to an int ('3455' --> 3455) and check if the condition holds
if 1 <= int(x) <= 25000:
    # Create a list of digits ('3455' --> ['3', '4', '5', '5'])
    lst = list(x)
    # Find unique digits (['3', '4', '5', '5'] --> {'3', '4', '5'})
    s = set(lst)
    # Count the number of unique digits
    c = len(s)
    # Print the result
    print(c)
else:
    # If the condition 1 <= x <= 25000 does not hold then print an error message
    print("Number should be >=1 and <=25000")

You one line solution does exactly the same thing. I would say that it's not very "clear", still it works (as long as you input a number, and not something else, such as "3455g").

Upvotes: 2

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