CODEWITHSUNDEEP
djangodjango-modelsdjango-queryset
IlConte
IlConte

Reputation: 159

Django Queryset get all values and first related

I need to get a json response with "customer" fields and the first phone number associated.

# models.py
class Customer(models.Model):
    
    name = models.CharField(max_length=255)
    surname = models.CharField(max_length=255,)
    ...

class CustomerPhone(models.Model):
    
    customer = models.ForeignKey(Customer, related_name = 'phones', on_delete=models.CASCADE)
    phone_number = PhoneNumberField()
    ...

My customer can have more phone numbers but in summary table I would like to see only the first phone (with min id)

When I try with this queryset:

Customer.objects.all().values('surname','phones__phone_number')

I obtain

<QuerySet [{'surname': 'Gates', 'phones__phone_number': '+39123456789'}, {'surname': 'Gates', 'phones__phone_number': '+3998765431'}, {'surname': 'Trump', 'phones__phone_number': '+32123456001'}, {'surname': 'Trump', 'phones__phone_number': '+3298765000'}]>

What I can obtain only one result for customer with only one phone number? what can I get

Upvotes: 1

Views: 730

Answers (2)

Diego Magalh&#227;es
Diego Magalh&#227;es

Reputation: 1762

Your relationship between CustomerPhone and Customer is a ForeignKey, so Customer will have a customer_phone_set field. What you need to do is:

 customer = Customer.objects.get(surname="example")
 first_phone_number = customer.customer_phone_set.first()

Upvotes: 1

willeM_ Van Onsem
willeM_ Van Onsem

Reputation: 476574

You can make use of a SubQuery expresssion [Django-doc]:

from django.db.models import OuterRef, Subquery

Customer.objects.values('surname').annotate(
    phone_number=Subquery(
        CustomerPhone.objects.filter(
            customer_id=OuterRef('pk')
        ).order_by('pk').values('phone_number')[:1]
    )
)

Upvotes: 3

Related Questions