CODEWITHSUNDEEP
xsltxslt-1.0
lightonphiri
lightonphiri

Reputation: 822

XSLT Document Function - Folder Hierarchy

I am working with xslt 1.0 and trying to use the XSLT document function to apply the stylesheet to a hierarchy of folders. The folder structures is as below, but I cannot seem to find any reliable references on the Web on how to do this.

a/
└── b
    └── c
        ├── d
        ├── e
        ├── f

Is there a way I can apply my stylesheet to nodes, in a file, in folder f via a file in folder a (a has links to file names in folder hierarchy).

Update #2

book01.xml
<?xml version="1.0" encoding="utf-8" ?>
<book location="../collection/book01.xml">
    <chapter>chapter001</chapteer>
</book>

chapter01.xml
<?xml version="1.0" encoding="utf-8" ?>
<chapter location="../collection/book01/chapter01.xml">
    <page>page01</page>
</chapter>

page01.xml
<?xml version="1.0" encoding="utf-8" ?>
<page location="../collection/book01/chapter01/page01.xml">
    <pagenumber>page 1</pagenumber>
    <text>
      page one.
    </text>
</page>

Output

Book Name: Book XX
  Chapter XX
    Page XX
      page xx.

Upvotes: 2

Views: 1256

Answers (3)

Emiliano Poggi
Emiliano Poggi

Reputation: 24826

I'm not sure this is a feasable/reasonable way to implement what you want achieve in the context of your use case; however, you can stay with you initial plan, that is working with xsl:for-each and document().

For example, assume you have the input file with the list of paths:

<files>
    <file>book001.xml</file>
    <file>chapter001.xml</file>
</files>

This input can be reasonably used to define a variable containing all your input documents and apply templates: 

<xsl:stylesheet
    xmlns:xsl="http://www.w3.org/1999/XSL/Transform"
    xmlns:msxsl="urn:schemas-microsoft-com:xslt"
    version="1.0">

    <xsl:template match="files">
        <xsl:variable name="docs">
            <docs>
                <xsl:for-each select="file">
                    <xsl:copy-of select="document(.)"/>
                </xsl:for-each>
            </docs>
        </xsl:variable>

        <xsl:apply-templates select="msxsl:node-set($docs)"/>
    </xsl:template>

    <!-- now you can match elements of your xml files -->

</xsl:stylesheet>

Notice that I needed the extension function in order to evaluate to a node-set. This is definetly available in xsltproc, or you can get it from EXSLT anyway.

In the example I've assumed that the input file is in the same folder of the book001.xml and chapter001.xml file.

Upvotes: 2

Michael Kay
Michael Kay

Reputation: 163498

Many XSLT 2.0 processors implement the collection() function in such a way as to allow you to interrogate directory structures in filestore. I'm not aware of any equivalent extensions in XSLT 1.0 processors.

Upvotes: 0

Max Toro
Max Toro

Reputation: 28618

If the links are relative then they are resolved against the base URI of the initial stylesheet, so that might not work. In XSLT 2.0 you have the resolve-uri function for that.

Maybe you could implement a resolve-uri extension function.

Upvotes: 0

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