CODEWITHSUNDEEP
pythonlistcountemoji
Pewtas
Pewtas

Reputation: 53

separate and count emojis in python list

I want to count the occurrences of Emojis in a list in python.

Assuming my list looks like this
li = ['😁', '🤣😁', '😁🤣😋']

Counter(li) would give me {'😁': 1, '🤣😁': 1, '😁🤣😋': 1}

But I would like to get the total amount of emojis aka {'😁': 3, '🤣': 2, '😋': 1}

My main issue is how to seperate large chunks of continous emoji into single list entries. I tried with replacing the beginning "\U" with " \U" so i could then simple split by " " but it does not seem to work.

Thanks for your help in advance :)

Upvotes: 2

Views: 599

Answers (3)

Reut Sharabani
Reut Sharabani

Reputation: 31339

One more way is to use the fact that counters implement addition:

>>> li = ['😁', '🤣😁', '😁🤣😋']
>>> from collections import Counter
>>> sum(map(Counter, li), Counter())
Counter({'😁': 3, '🤣': 2, '😋': 1})

Upvotes: 0

Thierry Lathuille
Thierry Lathuille

Reputation: 24232

You can count the emojis by iterating on the characters of each string:

from collections import Counter

li = ['😁', '🤣😁', '😁🤣😋']

count = Counter(emoji for string in li for emoji in string)

print(count)
# Counter({'😁': 3, '🤣': 2, '😋': 1})

@Dan gave a different answer just before me, which he sadly deleted since then, so I reproduce it for <10k users who can't see it:

Counter("".join(li))

I thought it might be less efficient because of the creation of the joined string, but I did some timings with small and larger lists up to 10 000 000 items, and it appears that his solution is consistently 30 to 40% faster.

Upvotes: 2

Dan
Dan

Reputation: 45752

You can flatten you list into a single string using join and then apply Counter to that:

Counter("".join(li))

results in

Counter({'😁': 3, '🤣': 2, '😋': 1})

or maybe a more memory efficient way is

counter = Counter()
for item in li:
    counter.update(item)

Upvotes: 6

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