Reputation: 9419
I have a list that displays 1, 2, and 3. When the text is tapped the app opens a sheet with the number tapped. However, if I tap the text in the second or third row, the number displayed in the sheet is still 1. What am I doing wrong?
import SwiftUI
struct ContentView: View {
var numbers = [1, 2, 3]
@State private var shouldPresentSheet = false
var body: some View {
List(self.numbers, id: \.self) { number in
Text("number: \(number)").sheet(isPresented: self.$shouldPresentSheet) {
Text("This is sheet number \(number)")
}.onTapGesture {
self.shouldPresentSheet.toggle()
}
}
}
}
Upvotes: 4
Views: 841
Reputation: 54466
You need to create one sheet instead of multiple sheets.
If you want to use .sheet(isPresented:content:)
you can do the following:
struct ContentView: View {
var numbers = [1, 2, 3]
@State private var selectedNumber: Int?
var body: some View {
List(numbers, id: \.self) { number in
Text("number: \(number)")
.onTapGesture {
self.selectedNumber = number
}
}
.sheet(isPresented: binding) {
Text("This is a sheet number \(self.selectedNumber ?? 0)")
}
}
var binding: Binding<Bool> {
.init(
get: { self.selectedNumber != nil },
set: { _ in }
)
}
}
Alternatively you can use .sheet(item:content:)
:
struct Model: Identifiable {
let id: Int
}
struct ContentView: View {
var numbers = [1, 2, 3].map(Model.init)
@State private var selectedNumber: Model?
var body: some View {
List(numbers, id: \.id) { number in
Text("number: \(number.id)")
.onTapGesture {
self.selectedNumber = number
}
}
.sheet(item: $selectedNumber) { item in
Text("This is a sheet number \(item.id)")
}
}
}
EDIT
If you decide to use .sheet(item:content:)
you can add an extension to Int
(instead of creating a custom struct conforming to Identifiable
):
extension Int: Identifiable {
public var id: Int { self }
}
as proposed in Asperi's answer.
Upvotes: 4