CODEWITHSUNDEEP
rustfloating-pointhexunsigned-integer
ANoobSwiftly
ANoobSwiftly

Reputation: 321

How to specify a floating point number literal using hexadecimal notation In Rust?

I'm implementing xoshiro256++ and I'm able to generate pseudo-random 64-bit unsigned integers. The next challenge is generating uniform doubles in the unit interval from the PRNGs u64's.

a 64-bit unsigned integer x should be converted to a 64-bit double using the expression

(x >> 11) * 0x1.0p-53

How would one evaluate this in Rust? On trying this I get the compile error:

error: hexadecimal float literal is not supported
  --> src/main.rs:30:56
   |
30 |             f64::from_bits((x >> 11).wrapping_mul(0x1.0p-53))
   |                                                        ^^^^^

Upvotes: 1

Views: 856

Answers (1)

Shepmaster
Shepmaster

Reputation: 432089

You can use the hexf crate:

#[macro_use]
extern crate hexf;

fn main() {
    let v = hexf64!("0x1.0p-53");
    println!("{}", v);
}

See also:

Upvotes: 2

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