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pbezpal
pbezpal

Reputation: 39

Scala how convert from Array to JSON format

I have to the code:

socket.emit("login",obj, new Ack {
         override def call(args: AnyRef*): Unit = {           
           println(args)
         }
       })

Console output

WrappedArray({"uid":989,"APILevel":5,"status":"ok"})

How to convert args from WrappedArray to JSON?

Upvotes: 0

Views: 129

Answers (1)

Tomer Shetah
Tomer Shetah

Reputation: 8529

There are many json libraries. For example you can take a look at Scala json parsers performance, to see the usage and performance. I'll demonstrate how that can be done using play-json. We need to first create a case class that represents your data model:

case class Model(uid: Int, APILevel: Int, status: String)

Now we need to create a formatter, on the companion object:

object Model {
  implicit val format: Format[Model] = Json.format[Model]
}

To create a JsValue from it, you can:

val input: String = "{\"uid\":989,\"APILevel\":5,\"status\":\"ok\"}"
val json: JsValue = Json.parse(input)

and to convert it to the model:

val model: Model = json.as[Model]

A complete running example can be found at Scastie. Just don't forget to add play-json as a dependency, by adding the following to your build.sbt:

resolvers += "play-json" at "https://mvnrepository.com/artifact/com.typesafe.play/play-json"
libraryDependencies += "com.typesafe.play" %% "play-json" % "2.9.1"

Upvotes: 1

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