Reputation: 285
I am trying to compare two arrays of objects as following :
const obj1 = [
{name:"Mark"},
{name:"David"},
{name:"Ellie"},
{name:"Zuank"},
{name:"Philip"},
{name:"Den"},
]
const obj2 = [
{name:"Mark"},
{name:"David"},
{name:"Zuank"},
{name:"Philip"},
]
I want to check if the name of every object exists in the second object or not. If yes, I want to push that object to a new array with a new property named "Matched" added to each object with a value of "true". Otherwise, the Matched property will be false. This is the final result I want to achieve :
const res = [
{ name: "Mark", matched: true },
{ name: "David", matched: true },
{ name: "Ellie", matched: false },
{ name: "Zuank", matched: true },
{ name: "Philip", matched: true },
{ name: "Den", matched: false },
]
--Edit Here is what I have tried so far guys :
obj1.map((element, index) => {
if (obj2[index].name === element.name) {
resArr.push({ name: element.name, matched: true })
}
else {
resArr.push({ name: element.name, matched: false })
}
})
Upvotes: 2
Views: 7420
Reputation: 56
Just map through obj1 and while mapping filter obj2 to check if the current name is in obj2. If it is then push the name along with the matched value of true into obj3. If it isn't then push the name along with the matched value of false into obj3.
const obj1 = [
{name:"Mark"},
{name:"David"},
{name:"Ellie"},
{name:"Zuank"},
{name:"Philip"},
{name:"Den"}
]
const obj2 = [
{name:"Mark"},
{name:"David"},
{name:"Zuank"},
{name:"Philip"}
]
let obj3 = []
obj1.map(function(a) {
let matched = obj2.filter(b => a.name === b.name);
if (matched.length) {
obj3.push({name: a.name, matched: true});
} else {
obj3.push({name: a.name, matched: false});
}
})
console.log(obj3);
Upvotes: 0
Reputation: 386560
You could take a Set
for all names and map the new property by checking the set.
const
array1 = [{ name: "Mark" }, { name: "David" }, { name: "Ellie" }, { name: "Zuank" }, { name: "Philip" }, { name: "Den" }],
array2 = [{ name: "Mark" }, { name: "David" }, { name: "Zuank" }, { name: "Philip" }],
names = new Set(array2.map(({ name }) => name)),
result = array1.map(o => ({ ...o, matched: names.has(o.name) }));
console.log(result);
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Upvotes: 0
Reputation: 138257
You could build a set of obj2:
const names = new Set(obj2.map(it => it.name));
Then mapping obj1 can be done in O(n):
const result = obj1.map(({ name }) => ({ name, matched: names.has(name) }));
Upvotes: 1
Reputation: 5999
You can make use of Array.map and Array.some.
const obj1 = [{name:'Mark'},{name:'David'},{name:'Ellie'},{name:'Zuank'},{name:'Philip'},{name:'Den'}];
const obj2 = [{name:'Mark'},{name:'David'},{name:'Zuank'},{name:'Philip'}];
const getProcessedResult = (data1, data2) => {
return data1.map(d1 => ({
...d1,
"matched": data2.some(d2 => d2.name === d1.name)
}));
}
console.log(getProcessedResult(obj1, obj2))
.as-console-wrapper {
max-height: 100% !important;
}
Upvotes: 0
Reputation: 14891
You could do a map
obj1
with some
on obj2 to check if obj1
element is on obj2
const obj1 = [
{ name: "Mark" },
{ name: "David" },
{ name: "Ellie" },
{ name: "Zuank" },
{ name: "Philip" },
{ name: "Den" },
]
const obj2 = [
{ name: "Mark" },
{ name: "David" },
{ name: "Zuank" },
{ name: "Philip" },
]
const res = obj1.map((el1) => ({
name: el1.name,
match: obj2.some((el2) => el2.name === el1.name),
}))
console.log(res)
Upvotes: 2
Reputation: 33726
You can use the function map
to build the desired output and the function some
to check for a specific object by the property name
.
const obj1 = [{name:"Mark"}, {name:"David"}, {name:"Ellie"}, {name:"Zuank"}, {name:"Philip"}, {name:"Den"}, ],
obj2 = [{name:"Mark"}, {name:"David"}, {name:"Zuank"}, {name:"Philip"}, ],
result = obj1.map(({name}) => ({name, matched: obj2.some(({name: name2}) => name2 === name)}));
console.log(result);
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Upvotes: 2