Reputation: 159
I've got a sequence that needs to sort a list based off earliest year vs. latest year. Due to some unique values in the year element, it is making the sort a little more complicated. Is there any way to achieve the following?
let $dates := ('1982', '2019', '2095', 'pre-1982', 'post-2095')
return
for $date in $dates
order by $date
return $date
the dates element text is usually the year in the data, but outlier cases have a pre- or post- attached. Any way to achieve this minimally?
Upvotes: 0
Views: 350
Reputation: 1895
Just FYI: Definitely not minimal, but I wanted to know what fn:sort
does when a sequence is returned. Turns out it does the right thing.
xquery version "3.1";
declare variable $local:ascending := 1;
declare variable $local:descending := -1;
declare function local:sort-prefixed-years ($y, $order) {
if (fn:contains($y, "-"))
then (
let $p := fn:tokenize($y, "-")
let $m :=
switch($p[1])
case "pre" return -1 * $order
case "post" return 1 * $order
default return 0
return (xs:integer($p[2]) * $order, $m)
)
else (xs:integer($y) * $order, 0)
};
declare function local:sort-prefixed-years-ascending ($prefixed-year) {
local:sort-prefixed-years($prefixed-year, $local:ascending)
};
declare function local:sort-prefixed-years-descending ($prefixed-year) {
local:sort-prefixed-years($prefixed-year, $local:descending)
};
let $dates := ('1982', '2019', '2095', 'pre-1982', 'post-2095')
return sort($dates, (), local:sort-prefixed-years-descending#1)
Upvotes: 0
Reputation: 1337
I am not sure if this is minimal, but it works:
let $dates := ('1982', '2019', '2095', 'pre-1982', 'post-2095')
return
for $date in $dates
let $year :=
if (fn:contains($date, "-"))
then fn:substring-after($date, "-")
else $date
let $prepost :=
if (fn:starts-with($date, "pre"))
then -1
else if (fn:starts-with($date, "post"))
then 1
else 0
order by $year, $prepost
return $date
Upvotes: 3