CODEWITHSUNDEEP
r
Tristan Tran
Tristan Tran

Reputation: 1543

Comparing lists element by element with NA and NULL

I am looking for some clean way to implement this operation. Say, I have a list as following:

gate_entry <- list(gate1 = "Andy",
                       gate2 = "Bob",
                       gate3 = "Chad",
                       gate4 = NA,
                       gate5 = " Dan",
                       gate6 = NA,
                       gate7 = NULL)

NA and NULL occurrences are possible and beyond my code's control.

Somewhere else in my codes, I register a list of the same length as gate_entry as following:

amount_carry <- list(10, 20, 15, NULL, NA, NA, NA)

For each element in gate_entry that is a non-empty string , I want to check if the corresponding element in amount_carry is numeric. If there is at least one occurrence where this condition is not true, return FALSE. Just like the elements in gate_entry, the elements in amount_carry could be NA or NULL. In this case, I expect element 1, 2, 3 and 5 in amount_carry to be numeric (and return TRUE). But since element 5 is NA, this operation should return FALSE.

Upvotes: 0

Views: 50

Answers (1)

MrFlick
MrFlick

Reputation: 206606

First, create a helper function to test for non-null, non-missing values

is_present <- function(x) !is.null(x) && !is.na(x)

We can test all the gate_entry and amount_carry values with

gate_ok <- sapply(gate_entry, is_present)
amount_ok <- sapply(amount_carry, is_present)

Now the only values that aren't allowed are when gate_ok is true but amount_ok is not so we just need to make sure there aren't any of those.

!any(gate_ok & !amount_ok)
# [1] FALSE

Upvotes: 3

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