Reputation: 1137
I've built a Java program as a front end for a database on a server, and I'm trying to use SSL to encrypt traffic between clients and the server. Here is the command I issued to create the server certificate:
keytool -genkey -alias localhost -keyalg RSA -keypass kpass123 -storepass kpass123 -keystore keystore.jks
Here is the relevant code:
System.setProperty("javax.net.ssl.keyStore",
"G:/Data/Android_Project/keystore.jks");
System.setProperty("javax.net.ssl.keyPassword", "kpass123");
SSLServerSocketFactory factory =
(SSLServerSocketFactory)SSLServerSocketFactory.getDefault();
SSLServerSocket accessSocket =
(SSLServerSocket)factory.createServerSocket(DB_ACCESS_PORT);
When I try to run this, I catch this:
java.security.NoSuchAlgorithmException: Error constructing implementation (algorithm: Default, provider: SunJSSE, class: com.sun.net.ssl.internal.ssl.DefaultSSLContextImpl)
I've also found that the "KeyPairGenerator" service has algorithms DIFFIEHELLMAN, DSA, RSA available to it, while "SSLContext" has algorithms SSL, TLS, SSLV3, DEFAULT, TLSV1.
Do I need to find some way to install RSA into the SSLContext service? Am I even looking at the correct services? Should I not be using RSA?
I'm new to the whole SSL - Security - Certificates thing, and it just blows me away that each of these different services don't have the same algorithms when they are supposed to be accessing the same certificates.
Upvotes: 42
Views: 220639
Reputation: 122769
Try javax.net.ssl.keyStorePassword
instead of javax.net.ssl.keyPassword
: the latter isn't mentioned in the JSSE ref guide.
The algorithms you mention should be there by default using the default security providers. NoSuchAlgorithmException
s are often cause by other underlying exceptions (file not found, wrong password, wrong keystore type, ...). It's useful to look at the full stack trace.
You could also use -Djavax.net.debug=ssl
, or at least -Djavax.net.debug=ssl,keymanager
, to get more debugging information, if the information in the stack trace isn't sufficient.
Upvotes: 80