CODEWITHSUNDEEP
pythonoop
coffe1
coffe1

Reputation: 11

Passing arguments self into function

How can I pass in arguments (a, b, c) to a function for a quadratic formula without having to redefine them in the function? I know I could use self.a instead of just a inside the formula (same thing for b and c) but how do I pass in the argument self.a as a, self.b as b, and self.c into the function?

class Calc:

    def __init__(self, a, b, c):
        self.a = a
        self.b = b
        self.c = c
    
    def quadraticformula(self):
        c = self.c
        b = self.b 
        a = self.a
        
        neg = ((b*-1)-(sqrt((b**2)-4*a*c)))/(2*a)
        pos = ((b*-1)+(sqrt((b**2)-(4*a*c))))/(2*a)
        return (pos,neg)

Upvotes: 0

Views: 68

Answers (2)

Maxim
Maxim

Reputation: 286

You don't have to redefine anything. The __init__ method allows for all other methods of the class to be able to access that variable. So once you actually define a variable you passed to the class (you referenced it as a function, which its not) in the __init__ method all you have to do it just reference it with whatever operation you need.

# within you quadraticformula method
...
neg = ((self.b*-1)-(sqrt(self.b**2 - 4*self.a*self.c)))/(2*self.a)
pos = ((self.b*-1)+(sqrt(self.b**2 - 4*self.a*self.c)))/(2*self.a)
return pos, neg

When passing attributes to the class you have create an instance of it like so:

a = # something
b = # something
c = # something

cl = Calc(a, b, c)
cl.quadraticformula() # call the method (a function with a method) of the function here

# You can call this method in the __init__ method if you want to 
# execute as soon as you call the class instead of using the instance 
# to reference it
class Calc:
  def __init__(self,a,b,c):
     self.a = a
     self.b = b
     self.c = c
     self.quadraticformula

Upvotes: 0

yungmaz13
yungmaz13

Reputation: 149

Instead of using a class with a constructor function just use a normal function in general

def calc(a, b, c):
    neg = ((b*-1)-(sqrt(b**2 - 4*a*c)))/(2*a)
    pos = ((b*-1)+(sqrt(b**2 - 4*a*c)))/(2*a)
    return pos, neg

Then call the function:

>>> calc(1, 2, -3)
(1.0, -3.0)

Upvotes: 2

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