CODEWITHSUNDEEP
cstringformatprintf
Mr. PHP
Mr. PHP

Reputation: 136

String printing excluding the first N characters

I want to print my string which is "Something" without the first N letters inside the printf statement.

Example 1: I can do the "opposite" (printf just N first letters):

#include <stdio.h>
int main() {
  char str[] = "Something";
  printf("%5s", str);
}

Output:Somet

Expected Output: hing

Upvotes: 1

Views: 716

Answers (3)

ryyker
ryyker

Reputation: 23218

There are many way to select where to start printing in a buffer. One potentially useful function, strchr(const char *buf, char ch), returns a pointer to the first occurrence of the char ch. So, If you want to begin printing at the letter h, then call strchr() in this way:

For expected output hing, use:

char str[]="Something";
printf("%s", strchr(str, 'h');

Or, for expected output omething, use:

printf("%s", strchr(str, 'o');

Another useful function: strstr(const char *source, const char *search) returns a pointer to any sub-string, search existing in the source buffer, so is also useful if you want to begin printing at a particular word in a larger buffer, for example given:

char longerStr[] = "This is really something else";
char *token = strstr(longerStr, "thing");
if(token)    //test before using to prevent trying to print a nul pointer in the event
{            //"thing" is not found in buffer.
    printf("%s", token);//note using " ", not ' '
}

Upvotes: 1

Vargo
Vargo

Reputation: 308

You could try using pointer arithmetic to pass the address of the starting point in the string where you want the printing to begin. In a more general context, you will need to somehow check that the number of character you are skipping is less than the total length of the main string.

#include<stdio.h>
int main()
{
    char str[]="Something";
    int numCharsToSkip = 5;

    printf("%s", (str + numCharsToSkip));
}

Upvotes: 1

klutt
klutt

Reputation: 31316

Start the printing in the middle:

printf("%s", &str[5]);

Upvotes: 1

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