CODEWITHSUNDEEP
javajavaparserinria-spoon
Iman
Iman

Reputation: 91

A faster way to build model in inria Spoon

I am using inria Spoon to parse Java projects, and then extract information about classes, Interfaces, fields, and methods and all their references.

I am using the below code to build model of an input project.

SpoonAPI spoonAPI = new Launcher();
spoonAPI.addInputResource(projectDirectory);
spoonAPI.buildModel();
CtModel ctModel = spoonAPI.getModel();

However, buildModel() is very time consuming in big projects.

PS: I used JavaParser using the below code and it is more faster than Spoon.

Path pathToSource = Paths.get(projectDirectory);
SourceRoot sourceRoot = new SourceRoot(pathToSource);
sourceRoot.tryToParse();
List<CompilationUnit> compilations = sourceRoot.getCompilationUnits();

I was wondering if there is any faster way to create the CtModel in Spoon.

Upvotes: 3

Views: 348

Answers (1)

Martin Monperrus
Martin Monperrus

Reputation: 2051

Instead of parsing the full source directory, you can build the model only for the files you need to analyze or transform:

spoonAPI.addInputResource("path/Foo.java"); 
spoonAPI.addInputResource("path/Bar.java");

Upvotes: 0

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