Reputation: 506
So I have a bq table that was created as several calender date snapshot, joined to trx data. Please find below query to populate the table
SELECT
GENERATE_DATE_ARRAY(date_add(DATE(CURRENT_TIMESTAMP), interval -20 day), DATE('2020-08-22')) AS date_array
)
,dim_date AS (
SELECT
sn_date
FROM
date_array_table,
UNNEST(date_array) AS sn_date
)
,data_test as (
select date('2020-08-20') as date, 1 as id, 1000 as num
UNION ALL
select date('2020-08-18') as date, 1 as id, 130 as num
UNION ALL
select date('2020-08-18') as date, 2 as id, 300 as num
UNION ALL
select date('2020-08-13') as date, 2 as id, 250 as num
)
,jjoin as (
select
*
from dim_date
left join
data_test
on 1=1 and sn_date = date
)
select *
from jjoin
order by 1 desc
The result is as following img
next I would like to fill the snapshot row with the NULL values with previous non NULL row by date for each id. I have tried to use max or first_value but it is still NULL. example :
select sn_date
coalesce(num, max (num) over (partition by id order by date)
from jjoin
but it doesn't show previous non Null row. any advice? thanks
expected :
--------------------------
sn_date | date | id | num
--------------------------
08/22 | 08/20| 1 | 1000
08/21 | 08/20| 1 | 1000
08/20 | 08/20| 1 | 1000
08/19 | 08/18| 1 | 130
08/18 | 08/18| 1 | 130
08/18 | 08/18| 2 | 300
08/17 | 08/13| 1 | 250
08/16 | 08/13| 1 | 250
08/15 | 08/13| 1 | 250
Upvotes: 2
Views: 2204
Reputation: 172994
Below is for BigQuery Standard SQL
#standardSQL
SELECT sn_date,
FIRST_VALUE(date IGNORE NULLS) OVER (win) AS date,
FIRST_VALUE(id IGNORE NULLS) OVER (win) AS id,
FIRST_VALUE(num IGNORE NULLS) OVER (win) AS num
FROM your_current_result
WINDOW win AS (ORDER BY sn_date DESC ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING)
If to apply to your current result shown in the question as in below example
#standardSQL
WITH your_current_result AS (
SELECT DATE '2020-08-20' sn_date, DATE '2020-08-20' date, 1 id, 1000 num UNION ALL
SELECT '2020-08-22', NULL, NULL, NULL UNION ALL
SELECT '2020-08-21', NULL, NULL, NULL UNION ALL
SELECT '2020-08-19', NULL, NULL, NULL UNION ALL
SELECT '2020-08-18', '2020-08-18', 1, 130 UNION ALL
SELECT '2020-08-18', '2020-08-18', 2, 300 UNION ALL
SELECT '2020-08-17', NULL, NULL, NULL UNION ALL
SELECT '2020-08-16', NULL, NULL, NULL UNION ALL
SELECT '2020-08-15', NULL, NULL, NULL UNION ALL
SELECT '2020-08-14', NULL, NULL, NULL UNION ALL
SELECT '2020-08-13', '2020-08-13', 1, 250
)
SELECT sn_date,
FIRST_VALUE(date IGNORE NULLS) OVER (win) AS date,
FIRST_VALUE(id IGNORE NULLS) OVER (win) AS id,
FIRST_VALUE(num IGNORE NULLS) OVER (win) AS num
FROM your_current_result
WINDOW win AS (ORDER BY sn_date DESC ROWS BETWEEN CURRENT ROW AND UNBOUNDED FOLLOWING)
result is
Row sn_date date id num
1 2020-08-22 2020-08-20 1 1000
2 2020-08-21 2020-08-20 1 1000
3 2020-08-20 2020-08-20 1 1000
4 2020-08-19 2020-08-18 1 130
5 2020-08-18 2020-08-18 1 130
6 2020-08-18 2020-08-18 2 300
7 2020-08-17 2020-08-13 1 250
8 2020-08-16 2020-08-13 1 250
9 2020-08-15 2020-08-13 1 250
10 2020-08-14 2020-08-13 1 250
11 2020-08-13 2020-08-13 1 250
Upvotes: 3
Reputation: 1269653
You can use last_value()
:
select sn_date, date, id, num,
last_value(date ignore nulls) over (order by date desc),
last_value(id ignore nulls) over (order by date desc),
last_value(num ignore nulls) over (order by date desc)
I should note that the SQL standard supports ignore nulls
on lag()
as well as first_value()
and last_value()
. When I think about solving this problem, I think in terms of lag()
. I think BigQuery is the only database that supports ignore null
s but not on lag()
.
Upvotes: 5