CODEWITHSUNDEEP
pythonpython-3.x
catzen
catzen

Reputation: 75

Create n instances of item in list and concatenate a string

I'm trying to create 5 instances of each item in a list, and for each of those, concatenate a string up till the value '5'.

my_list=['A','B','C']
scores=[]
n=0
for i in my_list:
    scores.append([my_list[n]]*5)
    n+=1
print(scores)

Output

[['A', 'A', 'A', 'A', 'A'], ['B', 'B', 'B', 'B', 'B'], ['C', 'C', 'C', 'C', 'C']]

scores_list=[]
n=1
for list_of_lists in scores:
    while n<6:
        scores_list.append(scores[0][0]+'_'+str(n))
        n+=1
print(scores_list)

Output

['A_1', 'A_2', 'A_3', 'A_4', 'A_5']

Expected

[['A_1', 'A_2', 'A_3', 'A_4', 'A_5'], ['B_1', 'B_2', 'B_3', 'B_4', 'B_5'], ['C_1', 'C_2', 'C_3', 'C_4', 'C_5']]

I've tried using more while loops but can't think of anything else. Any help would be appreciated.

Upvotes: 0

Views: 64

Answers (4)

Ahmed Mamdouh
Ahmed Mamdouh

Reputation: 706

Please use my code. It's very simple.

my_list=['A','B','C']

scores=[[f"{c}_{i+1}" for i in range(5)] for c in my_list]

print(scores)

Upvotes: -2

Prune
Prune

Reputation: 77837

Let's focus on your current programming level. A simple loop nesting will do the job. The value that changes the fastest, goes on the inside loop:

scores = []
for letter in "ABC":
    list_5 = []
    for number in range(1, 6):
        list_5.append(letter + '_' + str(number))

    scores.append(list_5)

print(scores)

Output:

[['A_1', 'A_2', 'A_3', 'A_4', 'A_5'], ['B_1', 'B_2', 'B_3', 'B_4', 'B_5'], ['C_1', 'C_2', 'C_3', 'C_4', 'C_5']]

Upvotes: 3

sahinakkaya
sahinakkaya

Reputation: 6056

Using a nested list comprehension:

>>> [[f"{char}_{num+1}" for num in range(5)] for char in my_list]
[['A_1', 'A_2', 'A_3', 'A_4', 'A_5'], ['B_1', 'B_2', 'B_3', 'B_4', 'B_5'], ['C_1', 'C_2', 'C_3', 'C_4', 'C_5']]

Upvotes: 1

Or Y
Or Y

Reputation: 2118

The problem in the original code is that you never reset the value of n back to one after the first iteration. but you can even skip the n variable by:

my_list=['A','B','C']
duplications = 5
scores=[]
for i in my_list:
    scores.append([f'{i}_{n}' for n in range(1, duplications+1)])
print(scores)

Output:

[['A_1', 'A_2', 'A_3', 'A_4', 'A_5'], ['B_1', 'B_2', 'B_3', 'B_4', 'B_5'], ['C_1', 'C_2', 'C_3', 'C_4', 'C_5']]

Upvotes: 0

Related Questions