Reputation: 279
I'm pattern matching on a tuple of two objects and want to match all cases where object1
is of the same type as object2
, something like
(object1, object2) match {
case (o1: T, o2: T) =>
// Ignore same objects case
case
.
.
.
case (_, _)
// Here I can be certain that the two object are not of the same type
Upvotes: 0
Views: 182
Reputation: 51723
Try
def test(object1: Any, object2: Any) = (object1, object2) match {
case (o1, o2) if o1.getClass == o2.getClass => println("same")
case (_, _) => println("different")
}
test(1, 2) //same
test(1, "2") //different
test(1: Any, "2": Any) //different
test(Some(1), Some("2")) //same
or
import scala.reflect.runtime.universe._
def getType[T: TypeTag](t: T): Type = typeOf[T]
def test[A: TypeTag, B: TypeTag](object1: A, object2: B) = (object1, object2) match {
case (o1, o2) if getType(o1) == getType(o2) => println("same")
case (_, _) => println("different")
}
test(1, 2) //same
test(1, "2") //different
test(1: Any, "2": Any) //same
test(Some(1), Some("2")) //different
or
def test[A, B](object1: A, object2: B)(implicit ev: A =:= B) = println("same")
test(1, 2) //compiles
// test(1, "2") //doesn't compile
test(1: Any, "2": Any) //compiles
// test(Some(1), Some("2")) //doesn't compile
If object1
and object2
are actually (case) objects then the easiest is
def test(object1: A, object2: A) = (object1, object2) match {
case (o1, o2) if o1 == o2 => println("same")
case (_, _) => println("different")
}
sealed trait A
case object B extends A
case object C extends A
test(B, B) //same
test(B, C) //different
Upvotes: 3
Reputation: 2527
Another variation to @Dmytro's answer:
Instead of TypeTag
, you could use ClassTag
import scala.reflect.ClassTag
def test[A: ClassTag, B: ClassTag](object1: A, object2: B): Unit =
(object1, object2) match {
case (_: A, _: A) => println("same")
case (_, _) => println("different")
}
test(1, 11) // same
test(1, "11") // different
Upvotes: 2