CODEWITHSUNDEEP
python
Lucas
Lucas

Reputation: 21

How can I delete the empty lines that appear on my python output?

I keep getting blank lines 1 when executing my code, I'm using a for loop to create this pattern 2, but i need to get rid of the spaces between the printed lines.

This is the code im using

n = int(input())
a = "_"
b = "|"
for i in range(0,n,1):
    if i == 0:
        print(" " * (2*n - 1) + "_*_")
        print(" " * 2*((n - 1)) + b + " " * 3 + b)
    else:
        print(" " * ((2*n - 1) - 2*i) + a + (" " * ((i + 1) * 4 - 3) ) + a)
        print(" " * ((2*(n-1)) - 2*i)  + b + (" " * ((i + 1)*4 - 1)) + b)

Upvotes: 2

Views: 96

Answers (2)

Olivier Samson
Olivier Samson

Reputation: 703

To add to flakes' answer, this is because the print() prints on a new line. This is why there is a space : instead of being on the same line, both caracters are on a separate line. As such, you should have a and b in the same print statement as shown by flakes

Upvotes: 0

flakes
flakes

Reputation: 23624

Lets break this down a bit and come up with some equations. First lets examine a possible output to see what the padding needs to be on the outer and inner parts of the pyramid.

       _*_         n=5, i=0, outer=7, inner=0
     _|   |_       n=5, i=1, outer=5, inner=3
   _|       |_     n=5, i=2, outer=3, inner=7
 _|           |_   n=5, i=3, outer=1, inner=11
|               |  n=5, i=4, outer=0, inner=15

For the inner, if i == 0 then inner = 0 otherwise inner = (4 * i) - 1

For the outer, if n - i == 1 then outer = 0 otherwise outer = (2 * (n - i - 1)) - 1

Now we can code this together:

for i in range(n):
    outer = " " * ((2 * (n - i - 1)) - 1)
    inner = " " * ((4 * i) - 1)

    if i == 0:
        # inner is 0
        print(outer + "_*_")
    elif n - i == 1:
        # outer is 0
        print("|" + inner + "|")
    else:
        print(outer + "_|" + inner + "|_")

Upvotes: 1

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