CODEWITHSUNDEEP
c#arrayslabel
markzzz
markzzz

Reputation: 47945

How to create an array with label and not integer

Suppose I have an array of strings like :

myArray["hello", "my", "name", "is", "marco"]

to access to this variable, I have to put an integer as index. So if I wanto to extract the third element I just do :

myArray[2]

Now, I'd like to use label instead of integer. So for example somethings like :

myArray["canada"]="hello";
myArray["america"]="my";
myArray["brazil"]="name";
myArray["gosaldo"]="is";
myArray["italy"]="marco";

How can I do this on C#? Is it possible? Thanks

Upvotes: 1

Views: 302

Answers (4)

Sven
Sven

Reputation: 22673

That's called an associative array, and C# doesn't support them directly. However, you can achieve exactly the same the effect with a Dictionary<TKey, TValue>. You can add values with the Add method (which will throw an exception if you try to add an already existing key), or with the indexer directly, as below (this will overwrite the existing value if you use the same key twice).

Dictionary<string, string> dict = new Dictionary<string, string>();

dict["canada"] = "hello";
dict["america"] = "my";
dict["brazil"] = "name";
dict["gosaldo"] = "is";
dict["italy"] = "marco";

Upvotes: 9

carlbenson
carlbenson

Reputation: 3207

With a Dictionary you will be able to set the "key" for each item as a string, and and give them string "values". For example:

Dictionary<string, string> dic = new Dictionary<string, string>();
dic.Add("canada", "hello");

Upvotes: 1

Tom Hazel
Tom Hazel

Reputation: 3502

C# has a Dictionary class (and interface) to deal with this sort of storage. For example:

Dictionary<string, string> dict = new Dictionary<string, string>();
dict.Add("canada", "hello");
dict.Add("america", "my");
dict.Add("brazil", "name");
dict.Add("gosaldo", "is");

Here are the docs: http://msdn.microsoft.com/en-us/library/xfhwa508.aspx

Upvotes: 1

m.edmondson
m.edmondson

Reputation: 30872

You're looking for an associative array and I think this question is what you're looking for.

Upvotes: 0

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