CODEWITHSUNDEEP
phpfile-get-contents
yikemop651
yikemop651

Reputation: 125

PHP - file_get_contents failed to open stream: No such file or directory even when file path is correct

I am trying to get content of a file with PHP. Then adding it inside a new file. I am using file_get_contents() but it shows the error:

PHP Warning:  file_get_contents(./home-starter.php): failed to open stream: No such file or directory

Even though the path is correct. Both files are in the same folder.

Main Folder
   errorfile.php
   home-starter.php

Any Suggestions?

<?php

require_once('private/initialize.php');

$city = 'Lahore';
$keyword = 'Homemade Food';
$areas = ['DHA', 'Bahria Town', 'Cantt', 'Gulberg', 'Valencia Town', 'Sui Gas Housing Society', 'Izmir Town', 'Faisal Town', 'Garden Town', 'Johar Town', 'Punjab Housing Society', 'Canal Housing Societies', 'State Life Housing Society', 'Model Town', 'Liaqatabad', 'Rehmanpura', 'Samanabad', 'Muslim Town', 'Town Ship', 'Iqbal Town', 'Ferozepure Road', 'Multan Road', 'Baghbanpura', 'Mughalpura', 'Walton'];

foreach ($areas as $area) {
  $permalink = strtolower(str_replace(' ', '-', $keyword)) . '-' . strtolower(str_replace(' ', '-', $area)) . '-' . strtolower($city);
  $page_title = 'Homemade Food Delivery - Lunch Dinner - ' . $area . ' - ' . $city;
  $meta_desc = 'Lunch.pk is Pakistan #1 website to order homemade food in ' . $area . ' ' . $city . '. You get tasty and healthy food cooked and delivered by families near you.';
  $location = $area . ' ' . $city;
  $filename = $permalink . '.php';

  $content = file_get_contents( __DIR__ . '/home-starter.php');
  $content = str_replace('[page-title]', $page_title, $content);
  $content = str_replace('[meta-desc]', $meta_desc, $content);
  $content = str_replace('[location]', $location, $content);

  $is_file_created = file_put_contents($filename, $content);

  if (!$is_file_created) {
    echo 'Err';
    break;
  }
}

Upvotes: 6

Views: 19398

Answers (4)

ZenMan16
ZenMan16

Reputation: 19

Check your PHP version supports __DIR__, i was able to get file content via a very similar method on PHP 7.4.24, but mine used a function that returns the contents.

$content = get_file_data("myfile.txt");

function get_file_data($filename) {
    $data = file_get_contents(__DIR__ . "/$filename");

    return $data;
}

Upvotes: 0

andreas-supersmart
andreas-supersmart

Reputation: 4294

I had this issue when implementing a cronjob after running the script successfully on a local dev machine.

My solution was to use the second function parameter of file_get_contents setting $use_include_path to TRUE

$currentFile = file_get_contents($fileinfo->getFilename(),true);

See the function's docs at php.net

Upvotes: 3

dılo s&#252;r&#252;c&#252;
dılo s&#252;r&#252;c&#252;

Reputation: 4201

check the file if exists then


$file=__DIR__ . '/home-starter.php'; 
if(file_exists($file))
{
   $content=file_get_contents($file);
}

you cant find the correct path, use getcwd() function get the current working directory

for example, your project has this structure

  • folder
    • app
    • model -> model.php
  • otherfolder
  • config ->config.php

assume you will get content of config.php in anywhere, you should use the below code


$content=file_get_contents(getcwd().'/config/config.php');

Upvotes: 5

Yogesh Wankhede
Yogesh Wankhede

Reputation: 73

You need to use physical url

./home-starter.php

e.g. file_get_contents('C:\xampp\htdocs\project1\home-starter.php');

Upvotes: 0

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