CODEWITHSUNDEEP
pythondictionarynestedkey-value
Fresh
Fresh

Reputation: 87

How to print multiple key values when a specifc key value matches in a nested dictionary

I have a nested dictionary that contains dictionaries of key value pairs pulled from json. For instance a nested dictionary called 'some_dict':

{1: {'address': 'some address', 'status': 'some status', 'name': 'some name'},
 2: {'address': 'some other address', 'status': 'some other status', 'name': 'some other name'}}

I need to search this nested dictionary for a specific value of key 'status', and when it matches, return all the values of that dictionary. However, I am continually receiving a key error in my implementation, and I can't figure out why.

# Based on this answer: https://stackoverflow.com/questions/9807634/find-all-occurrences-of-a-key-in-nested-dictionaries-and-lists

def has_key_value(data, target):
    for key, value in data.items():
        if isinstance(value, dict):
            yield from has_key_value(value, target)
        elif key == target:
            return true

for x in range(1, len(some_dict)):
    if has_key_value(x, 'some status'):
        #print the dictionary

I've gotten this far, but I can't for the life of me figure out how to return the contents of the dictionary in the nested some_dict. I have tried several things and finally came to this which sort of works:

for x in range(1, len(some_dict)):
    if has_key_value(x, 'some status'):
        print(some_dict[x])

Except after the first 3 dictionaries being printed it throws a 'KeyError: 4' error. I have checked that all the dictionaries within some_dict are identical in their schema so I can't figure out why the error. Thoughts?

Upvotes: 0

Views: 1185

Answers (1)

Barmar
Barmar

Reputation: 780909

You seem to be making this much more complicated than necessary. You don't seem to have multiple levels of nesting, so you don't have to recurse. And you only care of the status key matches the given value, not any other keys.

for d in some_dict.values():
    if d['status'] == 'some status':
        print(d)

Upvotes: 3

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