Ivan
Ivan

Reputation: 1527

Check whether a value exists in JSON object

I have the next JSON:

var JSONObject = {"animals": [{name:"cat"}, {name:"dog"}]};

What is the best way to know if the "dog" value exists in the JSON object?

Thanks.

Solution 1

var JSONObject = {"animals": [{name:"cat"}, {name:"dog"}]};
...
for (i=0; i < JSONObject.animals.length; i++) {
    if (JSONObject.animals[i].name == "dog")
        return true;
}
return false;

Solution 2 (JQuery)

var JSONObject = {"animals": [{name:"cat"}, {name:"dog"}]};
...
$.map(JSONObject.animals, function(elem, index) {
 if (elem.name == "dog") 
     return true;
});
return false;

Solution 3 (using some() method)

function _isContains(json, value) {
    let contains = false;
    Object.keys(json).some(key => {
        contains = typeof json[key] === 'object' ? 
        _isContains(json[key], value) : json[key] === value;
        return contains;
    });
    return contains;
}

Upvotes: 28

Views: 207298

Answers (9)

J.E.C.
J.E.C.

Reputation: 3012

Why not JSON.stringify and .includes()?

You can easily check if a JSON object includes a value by turning it into a string and checking the string.

console.log(JSON.stringify(JSONObject).includes("dog"))
--> true

Edit: make sure to check browser compatibility for .includes(), and this approach should be used only when the key names are known to not be the search value.

Upvotes: 6

Georgios Syngouroglou
Georgios Syngouroglou

Reputation: 20004

Because the "dog" you are looking for is inside of an array, then you may also use filter function, which returns always an array of items that much the filter criteria.
If the applied filter returns an empty array then no entries for "dog".

const JSONObject = {"animals": [{name: "cat"}, {name: "dog"}]}; // Your array

const exists = JSONObject.animals.filter(item => item.name === "dog").length > 0;
console.log("Exists? " + exists); // Exists: true

You may also get a count of how many times dog exists in your array.

const JSONObject = {"animals": [{name: "cat"}, {name: "dog"}]}; // Your array

const existsCount = JSONObject.animals.filter(item => item.name === "dog").length;
console.log("Exists: " + existsCount + " time(s)"); // Exists: 1 time(s)

Upvotes: 3

Dev Ydv
Dev Ydv

Reputation: 11

var JSONObject = {"animals": [{name:"cat"}, {name:"dog"}]};

 var Duplicate= JSONObject .find(s => s.name== "cat");
        if (typeof (Duplicate) === "undefined") {
           alert("Not Exist");
           return;
        } else {
            if (JSON.stringify(Duplicate).length > 0) {
                alert("Value Exist");
                return;
            }
        }

Upvotes: 1

Diego Pereira
Diego Pereira

Reputation: 91

I think this is the best and easy way:

$lista = @()

$lista += ('{"name": "Diego" }' | ConvertFrom-Json)
$lista += ('{"name": "Monica" }' | ConvertFrom-Json)
$lista += ('{"name": "Celia" }' | ConvertFrom-Json)
$lista += ('{"name": "Quin" }' | ConvertFrom-Json)

if ("Diego" -in $lista.name) {
    Write-Host "is in the list"
    return $true

}
else {
    Write-Host "not in the list"
    return $false
}

Upvotes: 0

solarbaypilot
solarbaypilot

Reputation: 69

You could improve on the answer from Ponmudi VN:

  • Shorter Code
  • Look for a key and a value

See this fiddle: https://jsfiddle.net/solarbaypilot/sn3wtea2/

function _isContains(json, keyname, value) {

return Object.keys(json).some(key => {
        return typeof json[key] === 'object' ? 
        _isContains(json[key], keyname, value) : key === keyname && json[key] === value;
    });
}

var JSONObject = {"animals": [{name:"cat"}, {name:"dog"}]};


document.getElementById('dog').innerHTML = _isContains(JSONObject, "name", "dog");
document.getElementById('puppy').innerHTML = _isContains(JSONObject, "name", "puppy");

Upvotes: 1

Gibolt
Gibolt

Reputation: 47287

Check for a value single level

const hasValue = Object.values(json).includes("bar");

Check for a value multi-level

function hasValueDeep(json, findValue) {
    const values = Object.values(json);
    let hasValue = values.includes(findValue);
    values.forEach(function(value) {
        if (typeof value === "object") {
            hasValue = hasValue || hasValueDeep(value, findValue);
        }
    })
    return hasValue;
}

Upvotes: 17

Ponmudi VN
Ponmudi VN

Reputation: 1553

Below function can be used to check for a value in any level in a JSON

function _isContains(json, value) {
    let contains = false;
    Object.keys(json).some(key => {
        contains = typeof json[key] === 'object' ? _isContains(json[key], value) : json[key] === value;
         return contains;
    });
    return contains;
 }

then to check if JSON contains the value

_isContains(JSONObject, "dog")

See this fiddle: https://jsfiddle.net/ponmudi/uykaacLw/

Most of the answers mentioned here compares by 'name' key. But no need to care about the key, can just checks if JSON contains the given value. So that the function can be used to find any value irrespective of the key.

Upvotes: 11

Vijay Sirigiri
Vijay Sirigiri

Reputation: 4721

var JSON = [{"name":"cat"}, {"name":"dog"}];

The JSON variable refers to an array of object with one property called "name". I don't know of the best way but this is what I do?

var hasMatch =false;

for (var index = 0; index < JSON.length; ++index) {

 var animal = JSON[index];

 if(animal.Name == "dog"){
   hasMatch = true;
   break;
 }
}

Upvotes: 23

Kevin Bowersox
Kevin Bowersox

Reputation: 94499

This example puts your JSON into proper format and does an existence check. I use jquery for convenience.

http://jsfiddle.net/nXFxC/

<!-- HTML -->
<span id="test">Hello</span><br>
<span id="test2">Hello</span>

//Javascript

$(document).ready(function(){
    var JSON = {"animals":[{"name":"cat"}, {"name":"dog"}]};

if(JSON.animals[1].name){      
$("#test").html("It exists");
}
if(!JSON.animals[2]){       
$("#test2").html("It doesn't exist");
}
});

Upvotes: 0

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