CODEWITHSUNDEEP
javascriptasynchronousasync-awaitcron
Ahmed
Ahmed

Reputation: 21

Async Functions with Node Cron

I have to run an async function written with Puppeteer (it's a bot) and I want to run that function every 60 seconds. The issue is that the async function (bot) runs for 2 min and so node cron automatically executes another async function which leads to 2 bot and 5s later it will launch another instance of this function.

What i want is to run 1st time then wait for 60s And after that execute it again. I'm so confused, it's my first NodeJS project.

const cron = require("node-cron")

cron.schedule("*/60 * * * * *", async () => {
    try {
        console.log(BotVote("Royjon94", "1"))
    }
    catch {
        console.log('error 404')
    }
})

Upvotes: 2

Views: 4277

Answers (1)

Eldar
Eldar

Reputation: 10790

I'm not sure cron is suitable for this kind of job. But basically you can achieve the same behavior with a basic while loop and a promise to await.

function delay(ms) {
  return new Promise(resolve => setTimeout(resolve, ms));
}

async function BotVote() {
  await new Promise(r => setTimeout(() => {
    console.log("voting");
    r();
  })) // for illusturation purpose  
}


async function worker() {
  let i = 0;
  let keepGoing = true;
  while (keepGoing) {
    await BotVote()
    await delay(600); // imagine it's 1minute.
    i++;
    if (i === 3) keepGoing = false; // decide when you stop
  }
}

worker();

Upvotes: 3

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