CODEWITHSUNDEEP
r
The Rookie
The Rookie

Reputation: 939

How do I print a single matrix from the code attached

The following code is returning 4 matrices -

n <- 5
for(i in range(n)){
  square_n = n*n
    for (j in range(n)){
      str1 = matrix(1:square_n, byrow=TRUE, nrow=n)
    print(str1)
    }
}

However when when I move the print(str1) "outside" the loop, it prints just one matrix (which is what I want). However what I'm doing calls for the print statement to be inside the loop. How do I correct my code.

Upvotes: 0

Views: 31

Answers (1)

akrun
akrun

Reputation: 887148

It is just updating the 'str1' on each iteration and the value we get is from the last iteration. print is just printing the value on the console on each iteration. If we want to store it, then have to create a list

str1 <- vector('list', 5)

Inside the loop, change the assignment line to

str1[[i]] <- matrix(1:square_n, byrow = TRUE, nrow = n)
print(str1[[i]])

-full code

for(i in range(n)){
  square_n = n*n
    for (j in range(n)){
      str1[[i]] = matrix(1:square_n, byrow = TRUE, nrow = n)
    print(str1[[i]])
    }
}

Upvotes: 1

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