CODEWITHSUNDEEP
xmlgomarshalling
Alex Semenov
Alex Semenov

Reputation: 142

GoLang XML marshalling customization (marshal without root element)

How to marshal without root element?

type Ids struct {
  Id []string `xml:"id"`
}

IdsStr, _ := xml.Marshal(&Ids{[]string{"test1", "test2"}})

Output IdsStr is:

<Ids><id>test1</id><id>test2</id></Ids>

It should be without Ids element:

<id>test1</id><id>test2</id>

Playground

Upvotes: 1

Views: 1946

Answers (2)

kozmo
kozmo

Reputation: 4515

...But how can I set voluntary xml names for elements? Vals []id xml:"idSomeOther" returns id after xml marshaled because it's name of type... I need to customize type id to type IdXml but xml marshaled should return id. How can I get it?

You can use XMLName xml.Name, tag xml:",chardata" (etc.) to customize a struct

type Customs struct {
    Vals []CustomXml
}

type CustomXml struct {
    XMLName xml.Name
    Chardata string `xml:",chardata"`
}

func main() {
    customs := Customs{
        []CustomXml{
            {XMLName: xml.Name{Local: "1"}, Chardata: "XXX"},
            {XMLName: xml.Name{Local: "2"}, Chardata: "YYY"}},
    }
    res, _ := xml.Marshal(customs.Vals)
    fmt.Println(string(res))
}

0utput

<1>XXX</1><2>YYY</2>

Playground

👉🏻 also, look at on src/encoding/xml/ to find examples.

Upvotes: 1

kozmo
kozmo

Reputation: 4515

type id string 

func main() {
    IdsStr, _ := xml.Marshal([]id{"test1", "test2"})
    fmt.Println(string(IdsStr))
}

Playground

or

type id string

type Ids struct {
    Vals []id 
}

func main() {
    ids := &Ids{[]id{"test1", "test2"}}
    IdsStr, _ := xml.Marshal(ids.Vals)
    fmt.Println(string(IdsStr))
}

Playground

0utput

<id>test1</id><id>test2</id>

Upvotes: 2

Related Questions