CODEWITHSUNDEEP
pythonschedule
LimNicholas97
LimNicholas97

Reputation: 21

Scheduling multiple schedules

I would like to start my code at the start of every hour I have tried using the minutes function of schedule however, the start time of the next process is dependent upon the end of the previous process and with the code I am trying to process the delay accumulates pretty quickly hence, I am trying this method instead. All help is appreciated. Thanks.

The code:

import schedule 
import time
schedule.every().day.at("00:00").do(consolidated)
schedule.every().day.at("01:00").do(consolidated)
schedule.every().day.at("02:00").do(consolidated)
schedule.every().day.at("03:00").do(consolidated)
schedule.every().day.at("04:00").do(consolidated)
schedule.every().day.at("05:00").do(consolidated)
schedule.every().day.at("06:00").do(consolidated)
schedule.every().day.at("07:00").do(consolidated)
schedule.every().day.at("08:34").do(consolidated)
schedule.every().day.at("09:00").do(consolidated)
schedule.every().day.at("10:00").do(consolidated)
schedule.every().day.at("11:00").do(consolidated)
schedule.every().day.at("12:00").do(consolidated)
schedule.every().day.at("13:00").do(consolidated)
schedule.every().day.at("14:00").do(consolidated)
schedule.every().day.at("15:00").do(consolidated)
schedule.every().day.at("16:00").do(consolidated)
schedule.every().day.at("17:00").do(consolidated)
schedule.every().day.at("18:00").do(consolidated)
schedule.every().day.at("19:00").do(consolidated)
schedule.every().day.at("20:00").do(consolidated)
schedule.every().day.at("21:00").do(consolidated)
schedule.every().day.at("22:00").do(consolidated)
schedule.every().day.at("23:00").do(consolidated)

while True:
    schedule.run_pending()
    time.sleep(1)

Upvotes: 1

Views: 436

Answers (1)

Randium
Randium

Reputation: 224

The schedule package has an option for doing a task every hour:

import schedule
import time

schedule.every().hour.do(consolidated)

while True:
    schedule.run_pending()
    time.sleep(1)

Upvotes: 2

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