CODEWITHSUNDEEP
javascriptarraysfilterjavascript-objects
Vorname Nachname
Vorname Nachname

Reputation: 139

JavaScript array of objects contains every element of another array

I have an array of objects (array1). I want to filter every element, that includes ALL of the tags ([1, 2, 3). So the result should be id 1. But i cannot make it work. The results i get are id 1, 2 ,4 and i do not understand why exactly it acts like this.

let array1 = [
  { id: 1, tags: [1, 2, 3] },
  { id: 2, tags: [2, 3] },
  { id: 3, tags: [0, 3] },
  { id: 4, tags: [1, 3] }
];

let tags = [1, 2, 3];

let includesAll = array1.filter((a1) =>
  a1.tags.every((tag) => tags.includes(tag))
);

console.log(includesAll);

Upvotes: 0

Views: 73

Answers (1)

trincot
trincot

Reputation: 350365

You should do the opposite. Instead of verifying that every value in a1.tags is also in tags, you'll want to verify that every value in tags is also in a1.tags:

let includesAll = array1.filter((a1) =>
  tags.every((tag) => a1.tags.includes(tag))
);


let array1 = [
  { id: 1, tags: [1, 2, 3] },
  { id: 2, tags: [2, 3] },
  { id: 3, tags: [0, 3] },
  { id: 4, tags: [1, 3] }
];

let tags = [1, 2, 3];

let includesAll = array1.filter((a1) =>
  tags.every((tag) => a1.tags.includes(tag))
);

console.log(includesAll);

Upvotes: 3

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