Reputation: 13
I'm trying get the following output with "FOR XML PATH".
<?xml version="1.0" encoding="utf-8"?>
<List Name=”test name”>
<Columns>
<c>Column1</c>
<c>Column2</c>
<c>Column3</c>
</Columns>
<Rows>
<r>
<v>Data1Column1</v>
<v>Data1Column2</v>
<v>Data1Column3</v>
</r>
<r>
<v>Data2Column1</v>
<v>Data2Column2</v>
<v>Data2Column3</v>
</r>
</Rows>
</List>
I'm trying to tackle the rows section with the following:
SELECT
[FA No.] as [v],
[Location] as [v]
FROM
sc.test_rd
FOR XML PATH (''), ROOT ('Row')
Which returns an output of:
<Row>
<v>6930151128</v>
<v>6931151128</v>
<v>6932151128</v>
<v>6945151990</v>
<v>6989151838</v>
</Row>
But I need the following:
<Row>
<v>6930</v><v>151128</v>
<v>6931</v><v>151128</v>
<v>6932</v><v>151128</v>
<v>6945</v><v>151990</v>
<v>6989</v><v>151838</v>
</Row>
Any help would be appreciated.
The Nulls worked , but now I have to combine this
SELECT COLUMN_NAME as [c/*]
FROM INFORMATION_SCHEMA.COLUMNS
where TABLE_NAME='test_rd'
FOR XML PATH ('') , ROOT ('Columns');
Which gives me an output of:
<Columns>
<c>id</c>
<c>FA No.</c>
<c>Location</c>
<c>Location Name</c>
<c>Line of Business</c>
<c>LOB Name</c>
<c>Area/CMU/Paypoint</c>
<c>Model Code</c>
</Columns>
with this
SELECT
[FA No.] as [v],
null,
[Location] as [v],
null,
[Line of Business] as [v],
null,
[Area/CMU/Paypoint] as [v],
null,
[Model Code] as [v]
FROM sc.test_rd
FOR XML path ('r') , Root ('Row')
Which gives me an output of this:
<Row>
<r>
<v>6930</v>
<v>151128</v>
<v>2100</v>
<v>2</v>
<v>CMU3+</v>
</r>
<r>
<v>6931</v>
<v>151128</v>
<v>2100</v>
<v>3</v>
<v>CMU3+</v>
</r>
<r>
<v>6932</v>
<v>151128</v>
<v>2100</v>
<v>1</v>
<v>CMU3+</v>
</r>
<r>
<v>6945</v>
<v>151990</v>
<v>2100</v>
<v>2</v>
<v>CMU3+</v>
</r>
<r>
<v>6989</v>
<v>151838</v>
<v>2100</v>
<v>2</v>
<v>CMU3+</v>
</r>
</Row>
Another sample of the desired output:
<?xml version="1.0" encoding="utf-8"?>
<List Name='test_rd' Action='Update'>
<Columns><c>FA No.</c><c>Location</c><c>Location Name</c><c>Line of Business</c><c>LOB Name</c><c>Area/CMU/Paypoint</c><c>Model Code</c></Columns>
<Rows>
<r><v>6930</v><v>151128</v><v>Viewmont Mall</v><v>2100</v><v>Strollers</v><v>1</v><v>CMU3+</v></r>
<r><v>6931</v><v>151128</v><v>Viewmont Mall</v><v>2100</v><v>Strollers</v><v>2</v><v>CMU3+</v></r>
<r><v>6932</v><v>151128</v><v>Viewmont Mall</v><v>2100</v><v>Strollers</v><v>3</v><v>CMU3+</v></r>
<r><v>6933</v><v>151128</v><v>Viewmont Mall</v><v>2100</v><v>Strollers</v><v>4</v><v>CMU3+</v></r>
<r><v>6934</v><v>151128</v><v>Viewmont Mall</v><v>2100</v><v>Strollers</v><v>5</v><v>CMU3+</v></r>
</Rows>
</List>
I also would like to add a CASE option, but I keep on getting an error?
-- test_rd
SELECT 'test_rd' as [@Name], 'Update' as [@Action]
, (
SELECT COLUMN_NAME as [c/*]
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME='test_rd' AND TABLE_SCHEMA = 'sc' and COLUMN_NAME != 'id'
FOR XML PATH (''), TYPE, ROOT ('Columns')
)
, (
SELECT
[FA No.] as [v],
NULL,
[Location] as [v],
NULL,
[Location Name] as [v],
NULL,
[Line of Business]as [v],
NULL,
[Line of Business Name]as [v],
CASE WHEN [Line of Business Name] = '0' THEN ''
WHEN [Line of Business Name] = '1' THEN 'lob1'
WHEN [Line of Business Name] = '2' THEN 'lob2'
End as [Line of Business Name],
NULL,
[Area/CMU/Paypoint] as [v],
NULL,
[Model Code] as [v]
FROM sc.test_rd
FOR XML path ('r'), TYPE, ROOT ('Rows')
)
FOR XML PATH('List')
-- test_rd
Lookup Error - SQL Server Database Error: Column name 'Line of Business Name' contains an invalid XML identifier as required by FOR XML; ' '(0x0020) is the first character at fault.
Upvotes: 1
Views: 519
Reputation: 22311
Here is a minimal reproducible example. I used AdventureWorks2012 database and its narrow Currency table with three columns.
SQL
USE AdventureWorks2012;
GO
SELECT 'test_rd' AS [@Name], 'Update' AS [@Action]
, (
SELECT COLUMN_NAME as [c/*]
FROM INFORMATION_SCHEMA.COLUMNS
WHERE TABLE_NAME='Currency' AND TABLE_SCHEMA = 'Sales' AND COLUMN_NAME != 'CurrencyCode'
FOR XML PATH (''), TYPE, ROOT ('Columns')
)
, (
SELECT TOP(2)
[CurrencyCode] as [v],
NULL,
[Name] as [v],
NULL,
[ModifiedDate] as [v]
FROM Sales.Currency
FOR XML path ('r'), TYPE, ROOT ('Row')
)
FOR XML PATH('List'), TYPE;
Output
<List Name="test_rd" Action="Update">
<Columns>
<c>Name</c>
<c>ModifiedDate</c>
</Columns>
<Row>
<r>
<v>AED</v>
<v>Emirati Dirham</v>
<v>2002-06-01T00:00:00</v>
</r>
<r>
<v>AFA</v>
<v>Afghani</v>
<v>2002-06-01T00:00:00</v>
</r>
</Row>
</List>
Upvotes: 0
Reputation: 82010
Take a peek at the following... notice the NULL
in the select
Example
Declare @YourTable Table ([FA No.] varchar(50),[Location] varchar(50))
Insert Into @YourTable Values
(6930,151128)
,(6931,151128)
,(6932,151128)
,(6945,151990)
,(6989,151838)
SELECT
[FA No.] as [v],
null,
[Location] as [v]
FROM @YourTable
FOR XML path ('') , Root ('Row')
Returns
<Row>
<v>6930</v>
<v>151128</v>
<v>6931</v>
<v>151128</v>
<v>6932</v>
<v>151128</v>
<v>6945</v>
<v>151990</v>
<v>6989</v>
<v>151838</v>
</Row>
EDIT -
A little unclear what you are looking for, but you can have a sub-query with the TYPE in you XML creation. Look at Rows =
and notice the ,TYPE
Example
Select [List/@Name] = YourNameColumn
,Rows = (
Select [FA No.] as [v],
null,
[Location] as [v]
From sc.test_rd
FOR XML path ('') , Root ('Row'),TYPE
)
From SomeTable
Upvotes: 1