CODEWITHSUNDEEP
pythonfunctiontuples
TKTK
TKTK

Reputation: 57

Returning a dictionary with 2 keys from a list of tuples within python

I've got a list of tuples which look like this.

people = [('John', 36, 'M'), ('Rachel', 24, 'F'), ('Deardrie', 78, 'F'), ('Ahmed', 17, 'M'), ('Sienna', 14, 'F')]

I'm trying to create a function. which has 2 parametres function(people, name) The function should return a dictionary with two keys, "age" and "gender", with the values being those from the tuple which contains the name passed as the second argument to the function. If the name isn't found in the list of tuples, return "None."

I'm struggling to create a function as i can't seem to find any information on how to approach a 3 element list of tuples.

any tips on how to approach this?

Upvotes: 0

Views: 1601

Answers (3)

Andok Hayruni
Andok Hayruni

Reputation: 1

Here is a function that returns list of dictionaries. If there are several tuples with the same name then the function returns all of them inside the list as a dictionaries. If there is not any tuple with the specific name then None is returned.

def my_f(people, name):
result = []
for each in people:
    if each[0] == name:
        result.append({'age': each[1], 'gender': each[2]})
if len(result) == 0:
    return None
return result

Upvotes: 0

Yossi Levi
Yossi Levi

Reputation: 1268

people = [('John', 36, 'M'), ('Rachel', 24, 'F'), ('Deardrie', 78, 'F'), ('Ahmed', 17, 'M'), ('Sienna', 14, 'F')]

def my_func(people, name:str):
    b = {}
    for person in people:
        if person[0] == name:
            b["Age"] = person[1]
            b["Gender"] = person[2]
    if len(b)>0:
        return b
    else:
        return None
        

c = my_func(people, 'Rachel')
print(c)
d = my_func(people, 'Diana')
print("\n" + str(d))

my output:

{'Age': 24, 'Gender': 'F'}

None

Upvotes: 0

Yash
Yash

Reputation: 1281

Something like this?

people1 = [('John', 36, 'M'), ('Rachel', 24, 'F'), ('Deardrie', 78, 'F'), ('Ahmed', 17, 'M'), ('Sienna', 14, 'F')]

def xyz(people, name):
    found={}
    for _name,_age,_gender in people:
        if _name==name:
            found["Age"]=_age
            found["Gender"]=_gender
            return found
    return None
    
print(xyz(people1,"John"))
print(xyz(people1,"John1"))

{'Age': 36, 'Gender': 'M'}
None

Upvotes: 2

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