Reputation: 88
I want to get the allItems variable outside the function, but I just can get an empty array. The first console.log shows the array I wanted, but the second it's just [].
var allItems = [];
orderPads.forEach(async element => {
element.orders_fk.forEach(async elem => {
let itemsArray = await OrderedItem.find({ order_fk: elem });
itemsArray.forEach(async e => {
let temp = e.toObject();
const mesa = await Table.findById(element.mesa);
temp.mesa = mesa.name;
allItems.push(temp)
console.log(allItems)
})
})
});
console.log(allItems)
I've already looked for answers online, but nothing seems to work in this case. Thank you for the help!
Upvotes: 4
Views: 8753
Reputation: 17330
Async functions don't do what you think they do in forEach
. Foreach will wait for every loop, but since it won't return a Promise
, you can't actually wait for all loops (the forEach
) to be done - the method will just return the current null immediately. Then you log that once. You might notice that your last log is logged first, and your others later, indicating that forEach
was completed, but the loops completed later, and your array only filled up after your first log.
Personally, I would suggest using a for
loop itself instead, which does not actually take you out of the async flow:
const allItems = [];
for( const element of orderPads ){
for( const elem of element.orders_fk ){
const itemsArray = await OrderedItem.find({ order_fk: elem });
for( const e of itemsArray ){
const temp = e.toObject();
const mesa = await Table.findById(element.mesa);
temp.mesa = mesa.name;
allItems.push(temp)
console.log(allItems)
}
}}
console.log(allItems)
for
loops are core constructs in Javascript, while forEach
is in essence a simplistic wrapper for a for
loop in Arrays that was never intended for asynchronous use.
Upvotes: 4