CODEWITHSUNDEEP
haskelltypesfunctional-programming
QCyrax
QCyrax

Reputation: 3

Why does my Haskell function return a type instead of a value?

I have difficulty understanding type creation in Haskell. I am trying to understand why the following Haskell function returns a type instead of a value:

data Exp = Enum Int

data Val = Vnum Int

eval :: Exp -> Val
eval (Enum x) = Vnum x

x :: Exp
x = Enum 2

When I run 'eval x', instead of returning 2 as I would expect, the interpreter returns 'eval x :: Val'. Enum and Vnum are merely tags, so basically, the eval function takes an "expression" as argument, which is in fact merely an integer, and returns a "value", which is also nothing more than an integer.

Like, of course eval x returns a Val, but why does the function not actually calculate the value and return it? I have the impression that the answer in kind of right in my face, but at the same time, I must be missing some elementary concept which is preventing me from noticing something that is probably obvious.

Thanks in advance for your help!

Upvotes: 0

Views: 273

Answers (1)

leftaroundabout
leftaroundabout

Reputation: 120751

Why does my Haskell function return a type

it doesn't. Your function works just fine and eval x does indeed give a value of type Val.

However note that an interpreter has no way to display this value – as far as it is concerned, this is a completely opaque type. At least GHCi makes this pretty clear:

<interactive>:3:1: error:
    • No instance for (Show Val) arising from a use of ‘print’
    • In a stmt of an interactive GHCi command: print it

Only if you say that you're really only interested in the type, by using the :t or :type directive, will it show just that:

> :t eval (Enum 2)
eval (Enum 2) :: Val

The easiest way to enable printing of values is to derive a Show instance:

data Val = Vnum Int   -- incidentally, this should probably be `newtype`,
 deriving (Show)      -- rather than `data`

> eval (Enum 2)
Vnum 2

Upvotes: 11

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