Reputation: 2426
I have an algorithm which generates combinations from entries of a container and I want to find the combination which minimizes a cost function:
struct Vec { double x; double y; };
double cost( Vec a, Vec b ) {
double dx = a.x - b.x;
double dy = a.y - b.y;
return dx*dx + dy*dy;
}
pair<Vec,Vec> get_pair_with_minimum_cost ( vector<Vec> inp, double (*cost_fun)(Vec,Vec) )
{
pair<Vec,Vec> result;
double min_cost = FLT_MAX;
size_t sz = inp.size();
for(size_t i=0; i<sz; i++) {
for (size_t j=i; j<sz; j++) {
double cost = cost_fun(inp[i], inp[j]);
if (cost < min_cost) {
min_cost = cost;
result = make_pair(inp[i], inp[j]);
}
}
}
return result;
}
vector <Vec> inp = {....};
auto best_pair = get_pair_with_minimum_cost ( inp, cost );
Unfortunately, get_pair_with_minimum_cost()
does 2 jobs:
I could break them in two functions, like:
template <class Func>
void generate_all_combinations_of( vector<Vec> inp, Func fun )
{
size_t sz = inp.size();
for(size_t i=0; i<sz; i++) {
for (size_t j=i; j<sz; j++) {
fun(make_pair(inp[i], inp[j]));
}
}
}
std::min_element
on the output of the generator, i.e.
vector<Vec> inp = {....};
vector<pair<Vec,Vec>> all_combinations;
generate_all_combinations_of(inp, [&](vector<pair<Vec,Vec>> o){all_combinations.push_back(o); } );
auto best_pair = *min_element(all_combinations.begin(), all_combinations.end(), cost);
but I do not want the pay the cost of creating and extra container with temporary data (all_combinations
).
Can I rewrite the generate_all_combinations_of()
such that it uses yield
or the new std::ranges
in such a way that I can combine it with STL algorithms such as find_if
, any_of
, min_element
or even adjacent_pair
?
The great thing about this 'generator' function is that it is easy to read, so I would like to keep it as readable as possible.
NB: some of these algorithms need to break
the loop.
What is the official name of combining entries this way? It this the combinations used in 'bubble-sort'.
Upvotes: 6
Views: 234
Reputation: 2051
Here's how I would write the function in c++17, using algorithms' min_element function, with no need for a separate container that stores the intermediate results. I know you were looking for a c++20 solution, but this code does work fine under c++20, and perhaps it gives you some ideas about adapting functions to ranges when the range isn't just one of the ranges supplied by c++20's ranges library.
// TwoContainerRanger is an iterable container where the iterator consists
// of two indices that match the given filter, and whose iterators, when
// dereferenced, return the result of calling func with the
// elements of the two containers, at those two indices.
// filter can be nullptr.
template <typename Container1, typename Container2, typename Func>
struct TwoContainerRanger {
Container1 &c1;
Container2 &c2;
const Func &fun;
bool (*restriction)(size_t i1, size_t i2);
TwoContainerRanger(Container1 &container1, Container2 &container2,
bool (*filter)(size_t i1, size_t i2), const Func &func)
: c1(container1), c2(container2), fun(func), restriction(filter) {}
struct Iterator {
const TwoContainerRanger *gen;
size_t index1, index2;
auto &operator++() {
do {
if (++index1 == gen->c1.size()) {
if (++index2 == gen->c2.size()) {
// we leave both indices pointing to the end
// to indicate that we have reached the end.
return *this;
} else {
index1 = 0u;
}
}
} while (gen->restriction && gen->restriction(index1, index2) == false);
return *this;
}
bool operator==(const Iterator &other) const = default;
bool operator!=(const Iterator &other) const = default;
auto operator*() const {
return gen->fun(gen->c1[index1], gen->c2[index2]);
}
};
Iterator begin() {
Iterator b{this, size_t(0) - 1, 0u};
return ++b; // automatically applies the restriction
}
Iterator end() { return Iterator{this, c1.size(), c2.size()}; }
};
Calling it looks like this:
int main() {
std::array<Vec, 5> ar = {Vec{0, 0}, Vec{1, 1}, Vec{3, 3}, Vec{7, 7},
Vec{3.1, 3.1}};
TwoContainerRanger tcr{ar, ar, Triangle, cost};
auto result = std::min_element(tcr.begin(), tcr.end());
std::cout << "Min was at (" << result.index1 << "," << result.index2
<< "); cost was " << *result << '\n';
}
Here's a demo.
Upvotes: 1
Reputation: 60228
Here's how I would write the function in c++20, using range views and algorithms so that there isn't a separate container that stores the intermediate results:
double get_minimum_cost(auto const & inp)
{
namespace rs = std::ranges;
namespace rv = std::ranges::views;
// for each i compute the minimum cost for all j's
auto min_cost_from_i = [&](auto i)
{
auto costs_from_i = rv::iota(i + 1, inp.size())
| rv::transform([&](auto j)
{
return cost(inp[i], inp[j]);
});
return *rs::min_element(costs_from_i);
};
// compute min costs for all i's
auto all_costs = rv::iota(0u, inp.size())
| rv::transform(min_cost_from_i);
return *rs::min_element(all_costs);
}
Here's a demo.
Note that the solution doesn't compare the cost between same elements, since the cost
function example you showed would have a trivial result of 0. For a cost function that doesn't return 0, you can adapt the solution to generate a range from i
instead of i + 1
. Also, if the cost
function is not symmetric, make that range start from 0 instead of i
.
Also, this function has UB if you call it with an empty range, so you should check for that as well.
Upvotes: 2
Reputation: 606
There is http://www.open-std.org/jtc1/sc22/wg21/docs/papers/2020/p2168r0.pdf who's development I would follow
If you are using MSVC, and can use their experimental/generator (not sure if others support it yet), you can use
std::experimental::generator<std::size_t> Generate(std::size_t const end){
for(std::size_t i = 0; i < end; ++i)
co_yield i;
}
int main(){
auto vals = Generate(22);
auto const result = *std::min_element(std::begin(vals),std::end(vals));
std::cout <<'\n' << " " << result;
}
Here you would need to modify the Generate function to Yield a pair/or to yield cost
(My recommendation would be to Keep things simple and yield the cost)
Then use vals to find min_cost
Based on what I can find about the Ranges Proposal, it works on the basis of std::begin and std::end both of which experimental::generator
provides
So it should probably work
Upvotes: 1