Reputation: 15665
#include <stdio.h>
#include <stdlib.h>
typedef struct nodeWords
{
char * word;
int index;
struct nodeWords *left;
struct nodeWords *right;
} nodeWords;
int main(void)
{
nodeWords * node = malloc(sizeof(*node));
printf("%lu\n",sizeof(*node));
node->left = NULL;
node->right = NULL;
nodeWords * ihash = malloc(2 * sizeof(*ihash));
printf("%p \n", node->left);
//this part not working
ihash[0] = *node->left;
printf("%p\n",ihash[0]);
}
How can I assign node->left
to ihash[0]
and then be able to print out ihash[0]
, which should point to NULL
?
Upvotes: 1
Views: 61
Reputation: 51825
There are two errors in your code and a few other 'minor issues' (I've commented these in the code posted below).
The first error is that you want to create an array of pointers to nodeWords
, so you will need two stars in the declaration of ihash
(one star will create an array of structure objects).
Second, in ihash[0] = *node->left;
, you are dereferencing node
twice (once with the preceding star operator, and once again with the ->
operator.
The following code fixes these issues:
#include <stdio.h>
#include <stdlib.h>
typedef struct nodeWords {
char* word;
int index;
struct nodeWords* left;
struct nodeWords* right;
} nodeWords;
int main(void)
{
nodeWords* node = malloc(sizeof(*node));
printf("%zu\n", sizeof(*node)); // Should really use "%zu" for size_t
node->left = NULL;
node->right = NULL;
nodeWords** ihash = malloc(2 * sizeof(*ihash)); // You want an array of POINTERS so you need two ** in the type!
printf("%p \n", (void*)node->left); // Pedantic: %p expects a void*
//this part not working
ihash[0] = node->left; // The "*" preceding "node" was an error: the "->" inherentlt derefernces node
// ihash[0] = (*node).left; // An alternative way of dong the same thing
printf("%p\n", (void*)ihash[0]); // Pedantic: %p expects a void*
// Don't forget to free the allocated memory...
free(ihash);
free(node);
return 0; // Always good practice to put this EXPLICIT return statement in your "main"
}
Upvotes: 1