Reputation: 11655
I want to put a copyright notice in the footer of a web site, but I think it's incredibly tacky for the year to be outdated.
How would I make the year update automatically with PHP
Upvotes: 1155
Views: 1560881
Reputation: 135
Using Carbon
$date = Carbon::now()->format('Y');
return $date;
In PHP
echo date("Y");
Upvotes: 6
Reputation: 3548
If you are using the Carbon PHP API extension for DateTime, you can achieve it easy:
<?php echo Carbon::now()->year; ?>
Upvotes: -3
Reputation: 881
My way to show the copyright, That keeps on updating automatically
<p class="text-muted credit">Copyright ©
<?php
$copyYear = 2017; // Set your website start date
$curYear = date('Y'); // Keeps the second year updated
echo $copyYear . (($copyYear != $curYear) ? '-' . $curYear : '');
?>
</p>
It will output the results as
copyright @ 2017 //if $copyYear is 2017
copyright @ 2017-201x //if $copyYear is not equal to Current Year.
Upvotes: 7
Reputation: 438
<?php date_default_timezone_set("Asia/Kolkata");?><?=date("Y");?>
You can use this in footer sections to get dynamic copyright year
Upvotes: 3
Reputation: 1152
Here's what I do:
<?php echo date("d-m-Y") ?>
below is a bit of explanation of what it does:
d = day
m = month
Y = year
Y will gives you four digit (e.g. 1990) and y for two digit (e.g. 90)
Upvotes: 15
Reputation: 2055
For up to php 5.4+
<?php
$current= new \DateTime();
$future = new \DateTime('+ 1 years');
echo $current->format('Y');
//For 4 digit ('Y') for 2 digit ('y')
?>
Or you can use it with one line
$year = (new DateTime)->format("Y");
If you wanna increase or decrease the year another method; add modify line like below.
<?PHP
$now = new DateTime;
$now->modify('-1 years'); //or +1 or +5 years
echo $now->format('Y');
//and here again For 4 digit ('Y') for 2 digit ('y')
?>
Upvotes: 7
Reputation: 5139
For 4 digit representation:
<?php echo date('Y'); ?>
2 digit representation:
<?php echo date('y'); ?>
Check the php documentation for more info: https://secure.php.net/manual/en/function.date.php
Upvotes: 17
Reputation:
print date('Y');
For more information, check date() function documentation: https://secure.php.net/manual/en/function.date.php
Upvotes: 11
Reputation: 12197
This one gives you the local time:
$year = date('Y'); // 2008
And this one UTC:
$year = gmdate('Y'); // 2008
Upvotes: 23
Reputation: 25251
My super lazy version of showing a copyright line, that automatically stays updated:
© <?php
$copyYear = 2008;
$curYear = date('Y');
echo $copyYear . (($copyYear != $curYear) ? '-' . $curYear : '');
?> Me, Inc.
This year (2008), it will say:
© 2008 Me, Inc.
Next year, it will say:
© 2008-2009 Me, Inc.
and forever stay updated with the current year.
Or (PHP 5.3.0+) a compact way to do it using an anonymous function so you don't have variables leaking out and don't repeat code/constants:
©
<?php call_user_func(function($y){$c=date('Y');echo $y.(($y!=$c)?'-'.$c:'');}, 2008); ?>
Me, Inc.
Upvotes: 220
Reputation: 23800
You can use either date or strftime. In this case I'd say it doesn't matter as a year is a year, no matter what (unless there's a locale that formats the year differently?)
For example:
<?php echo date("Y"); ?>
On a side note, when formatting dates in PHP it matters when you want to format your date in a different locale than your default. If so, you have to use setlocale and strftime. According to the php manual on date:
To format dates in other languages, you should use the setlocale() and strftime() functions instead of date().
From this point of view, I think it would be best to use strftime as much as possible, if you even have a remote possibility of having to localize your application. If that's not an issue, pick the one you like best.
Upvotes: 1455
Reputation: 10292
With PHP heading in a more object-oriented direction, I'm surprised nobody here has referenced the built-in DateTime
class:
$now = new DateTime();
$year = $now->format("Y");
or one-liner with class member access on instantiation (php>=5.4):
$year = (new DateTime)->format("Y");
Upvotes: 85
Reputation: 141
If your server supports Short Tags, or you use PHP 5.4, you can use:
<?=date("Y")?>
Upvotes: 5