dangost
dangost

Reputation: 13

Json to list of objects with marshmellow Python

I have json with data about my object I created schema for serialize it into list of objects, but it isn't work

Schema:

from marshmellow import fields, Schema

class ContactSchema(Schema):
    first_name = fields.String(attribute="ftNm")
    last_name = fields.String(attribute="ltNm")
    phone = fields.Integer(attribute="pn")

Model:

class Contact:
    id: int
    first_name: str
    last_name: str
    phone: str

And i have a function to convert (but is not working)

def json_to_list():
    json = [{'ftNm': 'Name1', 'ltNm': 'Surname1', 'pn': 343434},
            {'ftNm': 'Name2', 'ltNm': 'Surname2', 'pn': 141414}, 
            {'ftNm': 'Name3', 'ltNm': 'Surname3', 'pn': 656565}]

    schema = ContactSchema()
    result = schema.dump(json)

I will appreciate if someone help me with function to convert json to list of objects

Upvotes: 0

Views: 3118

Answers (2)

dangost
dangost

Reputation: 13

I do not know is it normally, but I just created a simple function and deserialize through the loop

    def create(self, json: dict):
        key = Key()
        key.id = json.get("id")
        key.key_number = json.get("num")
        key.hash = json.get("hash")

        return key

Upvotes: 0

Detlef
Detlef

Reputation: 8592

I'm not exactly sure what your intentions are. However, serialization and deserialization are possible in the following ways.

Serialization and deserialization with renaming of the attributes specified by the variable names.

from marshmallow import Schema, fields
    
class ContactSchema(Schema):
    first_name = fields.Str(attribute="ftNm", data_key="ftNm")
    last_name = fields.Str(attribute="ltNm", data_key="ltNm")
    phone = fields.Integer(attribute="pn", data_key="pn")

# serialization to json
def from_list():
    data = [
        {'ftNm': 'Name1', 'ltNm': 'Surname1', 'pn': 343434},
        {'ftNm': 'Name2', 'ltNm': 'Surname2', 'pn': 141414},
        {'ftNm': 'Name3', 'ltNm': 'Surname3', 'pn': 656565}
    ]
    schema = ContactSchema(many=True)
    return schema.dump(data)

# deserialization from json
def to_list():
    json = [
        {'ftNm': 'Name1', 'ltNm': 'Surname1', 'pn': 343434},
        {'ftNm': 'Name2', 'ltNm': 'Surname2', 'pn': 141414},
        {'ftNm': 'Name3', 'ltNm': 'Surname3', 'pn': 656565}
    ]
    schema = ContactSchema(many=True)
    return schema.load(json)

Deserialization without renaming of the attributes specified by the variable names.

class ContactSchema(Schema):
    first_name = fields.Str(attribute="ftNm")
    last_name = fields.Str(attribute="ltNm")
    phone = fields.Integer(attribute="pn")

# deserialization from json
def to_list():
    json = [
        {'first_name': 'Name1', 'last_name': 'Surname1', 'phone': 343434},
        {'first_name': 'Name2', 'last_name': 'Surname2', 'phone': 141414},
        {'first_name': 'Name3', 'last_name': 'Surname3', 'phone': 656565}
    ]
    schema = ContactSchema(many=True)
    return schema.load(json)

The direction of the conversion may not be indicated correctly.

from marshmallow import Schema, fields, post_load
from dataclasses import dataclass

@dataclass
class Contact:
    # id: int
    first_name: str
    last_name: str
    phone: str

class ContactSchema(Schema):
    first_name = fields.Str(data_key="ftNm")
    last_name = fields.Str(data_key="ltNm")
    phone = fields.Integer(data_key="pn")

    @post_load
    def make_user(self, data, **kwargs):
        return Contact(**data)

# deserialization from json
def to_list():
    json = [
        {'ftNm': 'Name1', 'ltNm': 'Surname1', 'pn': 343434},
        {'ftNm': 'Name2', 'ltNm': 'Surname2', 'pn': 141414},
        {'ftNm': 'Name3', 'ltNm': 'Surname3', 'pn': 656565}
    ]
    schema = ContactSchema(many=True)
    return schema.load(json)

To serialize and deserialize a database model, I recommend flask-marshmallow and marshmallow-sqlalchemy.

Upvotes: 2

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