CODEWITHSUNDEEP
pythonpython-3.xbeautifulsoup
Warok
Warok

Reputation: 403

TypeError: 'NoneType' object is not subscriptable with bs4

Here is my .xml file:

<?xml version="1.0" encoding="US-ASCII"?>
 <virtualhosts>
  <virtualhost id="113">
   <name>example.com</name>
   <hostname>myexample.com</hostname>
  </virtualhost>
 </virtualhosts>
</xml>

Now I want to extract the value of the id attribute of the virtualHost tag (in that case113) like described here. Here is my code:

import sys
from bs4 import BeautifulSoup as Soup

file ="temp.xml"
handler = open(file).read()
soup = Soup(handler,features="lxml")

for vHost in soup.find('virtualhost').find_all('name', string='example.com'):
    print(vHost.parent)#display the right level
    temp=vHost.parent.virtualhost['id']
    print(temp)

But I get the following error:

TypeError: 'NoneType' object is not subscriptable

Can someone help me?

Upvotes: 1

Views: 235

Answers (2)

KunduK
KunduK

Reputation: 33384

Since you have identified the parent just print this.

for vHost in soup.find('virtualhost').find_all('name', string='example.com'):
    print(vHost.parent)#display the right level
    temp=vHost.parent['id']
    print(temp)

Upvotes: 0

woblob
woblob

Reputation: 1377

You can use attrs function

Use contex manager so you don't have to remember about closing files.

import sys
from bs4 import BeautifulSoup as Soup

file ="temp.xml"
with open(file) as f:
    handler = f.read()
soup = Soup(handler,features="lxml")

all_names = soup.find('virtualhost').find_all('name', string='example.com')

for vHost in all_names:
    print(vHost.parent)#display the right level
    temp=vHost.parent.attrs['id']
    print(temp)

Upvotes: 1

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