Reputation: 14066
@Override
public int compareTo(final myRow another) {
final int BEFORE =-1;
final int EQUAL = 0;
final int AFTER = 1;
if (this==another) return EQUAL;
if (sorttype==sort_type.SORT_ABC) {
int rv =0;
int sorted =row.toLowerCase().compareTo(another.getRow().toLowerCase());
if (this.getUserType()==user_type.USER_TYPE_BANNED) rv=AFTER;
if (this.getUserType()==user_type.USER_TYPE_NORMAL) rv=sorted;
if (this.getUserType()==user_type.USER_TYPE_FRIEND) rv=BEFORE;
Log.e("sorted", row+" "+this.getUserType()+" - "+rv+" ");
return rv;
} else if (sorttype==sort_type.SORT_LOGINTIME) {
if (this.getUserType()==user_type.USER_TYPE_BANNED) {
return AFTER;
}
if (this.getUserType()==user_type.USER_TYPE_NORMAL) return EQUAL;
if (this.getUserType()==user_type.USER_TYPE_FRIEND) {
//int sorted =row.toLowerCase().compareTo(another.getRow().toLowerCase());
return BEFORE;
}
//return 0;
}
return 0;
//return row.toLowerCase().compareTo(another.getRow().toLowerCase());
}
I have a String userlist, with nick names. I have banned users, normal users, and friend users.
I d like to sort my friend users to the top of the list, and the banned users to the bottom of the list, and I d like to showing them is ASC style.
How can i do that?
So the structure is:
Abc (friend)
abrt (friend)
dfgh (friend)
abdfg (normal user)
bnmm (normal user)
wert (normal user)
Andgh (banned user)
Dfghhj (banned user)
Qwer (banned user)
I get this:
06-19 14:43:46.586: ERROR/AndroidRuntime(23434): java.lang.IllegalArgumentException: Comparison method violates its general contract!
Upvotes: 3
Views: 8797
Reputation: 14066
my code now :
public enum user_type {USER_TYPE_FRIEND(1), USER_TYPE_NORMAL(2), USER_TYPE_BANNED(3);
private final int order;
user_type(int order) {
this.order = order;
}
public int getOrder() {
return this.order;
}
}
...
@Override
public int compareTo(final myRow another) {
if (sorttype==sort_type.SORT_ABC) {
if (this.getUserType().equals(another.getUserType())) {
return this.getRow().toLowerCase().compareTo(another.getRow().toLowerCase());
} else {
return this.getUserType().compareTo(another.getUserType());
}
}
else {
//LOGINTIME
return this.getUserType().compareTo(another.getUserType());
}
}
Thanks, Sanjay!
Upvotes: 0
Reputation: 23218
Your code looks a bit complex. The simplest way would be to start from the highest priority field and move down to other fields. An example code would be:
public class Member implements Comparable<Member> {
static enum Status {
NORMAL(1), FRIEND(2), BANNED(3);
private final int order;
Status(int order) {
this.order = order;
}
public int getOrder() {
return this.order;
}
};
private final String name;
private final Status status;
public Member(final String name, final Status status) {
this.name = name;
this.status = status;
}
@Override
public int compareTo(Member o) {
if (this.status.equals(o.status)) {
return this.name.compareTo(o.name);
} else {
return this.status.compareTo(o.status);
}
}
@Override
public String toString() {
return "Member [name=" + name + ", status=" + status + "]";
}
public static void main(String[] args) throws Throwable {
Member[] members = {
new Member("abrt", Status.FRIEND),
new Member("dfgh", Status.FRIEND),
new Member("abdf", Status.NORMAL),
new Member("wert", Status.NORMAL),
new Member("andgh", Status.BANNED),
new Member("qwer", Status.BANNED)
};
List<Member> lst = Arrays.asList(members);
Collections.sort(lst);
System.out.println(lst);
}
}
Upvotes: 5
Reputation: 206841
Your ABC sort logic doesn't work. If you pass in two USER_TYPE_FRIEND
objects for instance, whatever their respective order, compareTo
will always return BEFORE
.
You need to implement this by first comparing the usertype.
If they are equal, you can return your row.compareTo(...)
expression.
If not, you need to return before/after depending only on how those types "compare" in your logic (i.e. friend < normal < banned).
Upvotes: 1