CODEWITHSUNDEEP
iosswiftalamofire
Peterses
Peterses

Reputation: 937

Parse alamofire response into JSON return nil

I'm trying to parse data from alamofire response. If i print all response it works good, but if i want to print specific parametr form JSON, for example "firstName" it is returning nil.

    AF.request("http://localhost:5000/api/users").responseJSON(completionHandler: { (res) in
        
        switch res.result {
        case let .success(value):

            let xjson : JSON = JSON(res.value)
            print(xjson["firstName"].string)

        case let .failure(error):
            print(error)
        }
    })

No errors in console

Code below

    AF.request("http://localhost:5000/api/users").responseJSON(completionHandler: { (res) in
        
        switch res.result {
        case let .success(value):

            let xjson : JSON = JSON(res.value)
            print(xjson)
            print(xjson["firstName"].string)
        case let .failure(error):
            print(error)
        }
        
    })

returns

[
  {
    "dateOfBirth" : "1998-11-18T00:00:00.000Z",
    "_id" : "5f6a29ed16444afd36e9fe15",
    "email" : "[email protected]",
    "__v" : 0,
    "firstName" : "adam",
    "lastName" : "kowalski",
    "accountCreateDate" : "2020-09-22T16:44:29.692Z",
    "userPassword" : "12345",
    "userLogin" : "loginakowalski"
  }
]
nil

Upvotes: 1

Views: 286

Answers (2)

Peterses
Peterses

Reputation: 937

Thanks to everyone for your help. Below is the code that returns the correct value:

    AF.request("http://localhost:5000/api/users").responseJSON(completionHandler: { (res) in
        
        switch res.result {
        case let .success(value):

            let xjson : JSON = JSON(res.value)
            if let firstUser = xjson.array?.first {
                print(firstUser["firstName"].string!)
            }
        
        case let .failure(error):
            print(error)
        }
    })

Upvotes: 1

Kamran
Kamran

Reputation: 15248

This xjson is an Array of JSON(looks User) objects. So you need to access the array elements as below,

let xjson : JSON = JSON(res.value)
if let firstUser = xjson.array?.first {
    print(firstUser["firstName"] as? String)
}

You can also put your JSON response here and get the required data types and decoding code for free.

Upvotes: 2

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