Reputation: 14977
I have a dataframe timings
as follows:
start_ms end_ms
0 2020-09-01T08:11:19.336Z 2020-09-01T08:11:19.336Z
1 2020-09-01T08:11:20.652Z 2020-09-01T08:11:20.662Z
2 2020-09-01T08:11:20.670Z 2020-09-01T08:11:20.688Z
I'm trying to calculate the time difference between the start_ms
and end_ms
of each row in milliseconds, i.e. I wish to get the result
start_ms end_ms diff
0 2020-09-01T08:11:19.336Z 2020-09-01T08:11:19.336Z 0
1 2020-09-01T08:11:20.652Z 2020-09-01T08:11:20.662Z 10
2 2020-09-01T08:11:20.670Z 2020-09-01T08:11:20.688Z 18
I can convert the timestamp to datetime column by column, but I'm not sure if the order of the values are retained.
start_ms_time = pd.to_datetime(timings['start_ms'])
end_ms_time = pd.to_datetime(timings['end_ms'])
Is it possible to convert the timestamps to datetime inside timings
, and add the time difference column? Do I even need to convert to get the difference? How do I calculate the time difference in milliseconds?
Upvotes: 4
Views: 1437
Reputation: 862681
Subtract columns by Series.sub
and then use Series.dt.components
:
start_ms_time = pd.to_datetime(timings['start_ms'])
end_ms_time = pd.to_datetime(timings['end_ms'])
timings['diff'] = end_ms_time.sub(start_ms_time).dt.components.milliseconds
print (timings)
start_ms end_ms diff
0 2020-09-01T08:11:19.336Z 2020-09-01T08:11:19.336Z 0
1 2020-09-01T08:11:20.652Z 2020-09-01T08:11:20.662Z 10
2 2020-09-01T08:11:20.670Z 2020-09-01T08:11:20.688Z 18
Or Series.dt.total_seconds
with multiple by 1000
and cast to integers:
timings['diff'] = end_ms_time.sub(start_ms_time).dt.total_seconds().mul(1000).astype(int)
print (timings)
start_ms end_ms diff
0 2020-09-01T08:11:19.336Z 2020-09-01T08:11:19.336Z 0
1 2020-09-01T08:11:20.652Z 2020-09-01T08:11:20.662Z 10
2 2020-09-01T08:11:20.670Z 2020-09-01T08:11:20.688Z 18
Upvotes: 4