Reputation: 461
i want to replace all rows that have "A" in name column with single row from another df
i got this
data={"col1":[2,3,4,5,7],
"col2":[4,2,4,6,4],
"col3":[7,6,9,11,2],
"col4":[14,11,22,8,5],
"name":["A","A","V","A","B"],
"n_roll":[8,2,1,3,9]}
df=pd.DataFrame.from_dict(data)
df
that is my single row (the another df)
data2={"col1":[0]
,"col2":[1]
,"col3":[5]
,"col4":[6]
}
df2=pd.DataFrame.from_dict(data2)
df2
that how i want it to look like
data={"col1":[0,0,4,0,7],
"col2":[1,1,4,1,4],
"col3":[5,5,9,5,2],
"col4":[6,6,22,6,5],
"name":["A","A","V","A","B"],
"n_roll":[8,2,1,3,9]}
df=pd.DataFrame.from_dict(data)
df
i try do this df.loc[df["name"]=="A"][df2.columns]=df2
but it did not work
Upvotes: 2
Views: 438
Reputation: 150735
df.loc[df["name"]=="A"][df2.columns]=df2
is index-chaining and is not expected to work. For details, see the doc.
You can also use boolean indexing like this:
df.loc[df['name']=='A', df2.columns] = df2.values
Output:
col1 col2 col3 col4 name n_roll
0 0 1 5 6 A 8
1 0 1 5 6 A 2
2 4 4 9 22 V 1
3 0 1 5 6 A 3
4 7 4 2 5 B 9
Upvotes: 2
Reputation: 323226
We can try mask
+ combine_first
df = df.mask(df['name'].eq('A'), df2.loc[0], axis=1).combine_first(df)
df
col1 col2 col3 col4 name n_roll
0 0 1 5 6 A 8.0
1 0 1 5 6 A 2.0
2 4 4 9 22 V 1.0
3 0 1 5 6 A 3.0
4 7 4 2 5 B 9.0
Upvotes: 4