CODEWITHSUNDEEP
javascriptconditional-operatorlogical-or
Monu
Monu

Reputation: 21

JavaScript Ternary with Logical OR

var a = '1';
console.log(a == ('2'||'1')?'hi':'hello');

Doing so the condition get failed as a = 1 . It is comparing a's value 1 with 2 as this condition failed. so it always print hello. Is there any way to check for value('1') also which is after "||" so that it print hi?

Upvotes: 1

Views: 71

Answers (2)

Monu
Monu

Reputation: 21

var a = 1; a == '2'?'hi': a=='1'?'hello' :'';

i Found this is also working.... Thanks to everyone who answered using different ways..

Upvotes: 0

CertainPerformance
CertainPerformance

Reputation: 370979

Either list the different possibilities out separately:

a === '2' || a === '1' ? 'hi' : 'hello'

Or use an array and .includes:

['2', '1'].includes(a) ? 'hi' : 'hello'

The problem with ('2'||'1') is that the whole section there gets evaluated to a single expression before the comparison against a is made, and || will evaluate to the initial value if it's truthy. So ('2' || '1') resolves to '2'.

Upvotes: 5

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